Simplified Mechanics and Strength of MaterialsWiley, 1951 - 275 páginas |
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Página 5
... Resultant and Components . The resultant of a system of forces is the simplest system ( usually a single force ) that has the same effect as the various forces in the system acting simul- taneously . The lines of action of any system of ...
... Resultant and Components . The resultant of a system of forces is the simplest system ( usually a single force ) that has the same effect as the various forces in the system acting simul- taneously . The lines of action of any system of ...
Página 20
... resultant . Therefore , we draw the resultant , whose magnitude and direction are found in the force polygon , through the point of intersection of strings oa and oe and thus completely determine the resultant . 24. Resultant of ...
... resultant . Therefore , we draw the resultant , whose magnitude and direction are found in the force polygon , through the point of intersection of strings oa and oe and thus completely determine the resultant . 24. Resultant of ...
Página 23
... resultant of two parallel forces having the same direction is equal to their sum , in this instance 50 + 100 150 # . = Figure 19 ( e ) shows two parallel forces of 90 # and 30 # , 10 ' apart , having opposite directions . Their resultant ...
... resultant of two parallel forces having the same direction is equal to their sum , in this instance 50 + 100 150 # . = Figure 19 ( e ) shows two parallel forces of 90 # and 30 # , 10 ' apart , having opposite directions . Their resultant ...
Contenido
CHAPTER | 1 |
Elements of a Force | 9 |
Equilibrant | 15 |
Derechos de autor | |
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allowable axial load allowable load allowable unit stress angle bars center of moments centroid column compressive stresses compressive unit stress Compute the maximum concentrated load cross section cross-sectional area deflection deformation determine diameter distance double bearing elastic limit EXAMPLE EXAMPLE factor of safety fillet weld flexure formula force polygon free body diagram funicular polygon hence indicated in Fig inertia intersection length line of action linear foot magnitude material maximum bending maximum shear modulus of elasticity moment of inertia neutral surface parallel parallelogram of forces pier plate pounds per linear pounds per square pressure PROBLEMS R₁ radius of gyration reactions reinforced concrete resisting respect resultant rivet rods section modulus shaft shear diagram shearing stress shearing unit stress shown in Fig simple beam single bearing slenderness ratio SOLUTION span square inch stirrups Table tensile stresses thickness three forces truss uniformly distributed load weight width zero