| Euclid, John Keill - 1733 - 444 páginas
...unequal to EF, therefore it is equal to it. But AB is alfo equal to D E. Wherefore the two Sides AB, **BC, are equal to the two Sides DE, EF, each to each ; and** they cpntain equal Angles. And fo the Bafe AC is equal to the Bafe DF, the Triangle BAC to the Triangle... | |
| John Keill - 1772 - 462 páginas
...which let be AB, make GB equal to DE, and join <3 C. t Then, becaufe BG is equal to DE, and BC to EF, **the two Sides GB, BC, are equal to the two Sides DE,...equal to the Angle DE F. The Bafe GC is * equal to** th«» 4 »/'««• Bafe DF, and the Triangle GBC to the Triangle DEF, and the remaining Angles equal... | |
| Euclid, James Williamson - 1781 - 324 páginas
...DE, EF 1 ~" v ~~' each to each; and the angle GBC is equal (by fupp.) to DEF: therefore (by prop. 4.) **the bafe GC is equal to the bafe DF; and the triangle** GCB will be equal to the triangle DEF; and the remaining angles will be equal to the remaining angles,... | |
| Euclid, John Playfair - 1795 - 462 páginas
...equal to the two DE,. EF, each to each; and the angle GBC is.equal to the angle DEF ; therefore me **bafe GC is equal » to the bafe DF, and the triangle GBC to the triangle DEF, and the** other angles to the other angles, each, to each,, to. which the equal fideS are oppofite ; thereforei... | |
| John Playfair, Euclid - 1804 - 468 páginas
...equal to the two DE, FT, each to each ; and the angle GBC is equal to the angle DEF; therefore the bale **GC is equal" to the bafe DF, and the triangle GBC to the triangle DEF, and the** other angles to the other angles, each to each, to which the equal fides are oppofite ; therefore the... | |
| Pierce Morton - 1830 - 584 páginas
...will be between L and B. Join QC: and, because the triangles Q В С, DEF have the two sides QB, В С **equal to the two sides DE, EF, each to each, and the** included angles equal to one another, the third sides QC, DF are equal to one another (13.) ; and,... | |
| 1835 - 684 páginas
...will be between L and B. Join QC: and, because the triangles QBG, DEF have the two sides QB, В С **equal to the two sides DE, EF, each to each, and the** included angles equal to one another, the third sides QC, DF are equal to one another (13.) ; and,... | |
| John Playfair - 1836 - 148 páginas
...equal to DE, and join CG ; therefore, because BG is equal to DE, and BC to EF, the two sides GB, BC arc **equal to the two sides DE, EF, £ each to each ; and the angle GBC** is equal to the angle DEF ; therefore the base CG is equal (4.1.) to the base DF, and the triangle... | |
| Euclides - 1855 - 270 páginas
...EF ; that is, B С is equal to K F. And AB is equal (Hyp.) to D E. Therefore the two sides AB, B С **are equal to the two sides DE, EF, each to each. And the angle** AB С is equal (Hyp.) to the angle DE F. Therefore the base A С is equal (I. 4) to the base DF, and... | |
| Euclides - 1862 - 140 páginas
...Demonstration. — 1. Because BG is assumed to be equal to DE (const.), and BC is equal to EF (hyp.), **the two sides GB, BC, are equal to the two sides DE, EF, each to each.** 2. And the angle GBC is equal to the angle DEF, (hyp.) 3. Therefore the base GC is equal to the base... | |
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