Elements of Geometry: With, Practical ApplicationsD. Appleton and Company, 1850 - 320 páginas |
Dentro del libro
Resultados 1-5 de 57
Página 49
... altitude of the parallelogram ABCD . 5. The altitude of a trapezoid is the perpendicular drawn be- tween its two parallel sides ; thus , FG is the altitude of the trapezoid ABCD . A A D F DF 6. A rectangle is said to be con- D tained 5 ...
... altitude of the parallelogram ABCD . 5. The altitude of a trapezoid is the perpendicular drawn be- tween its two parallel sides ; thus , FG is the altitude of the trapezoid ABCD . A A D F DF 6. A rectangle is said to be con- D tained 5 ...
Página 50
... altitude ; then will they be equivalent . DF G F D B Since they have the same altitude , their upper bases will be in the same line GC , parallel to the common base AB . We have BC equal to AD , and BF equal to AG ; we also have DC ...
... altitude ; then will they be equivalent . DF G F D B Since they have the same altitude , their upper bases will be in the same line GC , parallel to the common base AB . We have BC equal to AD , and BF equal to AG ; we also have DC ...
Página 51
... altitude , are equivalent . Let the two triangles ABC , ABD have the same base AB , and the same altitude ; then will they be equivalent . D A B their vertices will be Draw AF parallel to Since they have the same altitude , the line CD ...
... altitude , are equivalent . Let the two triangles ABC , ABD have the same base AB , and the same altitude ; then will they be equivalent . D A B their vertices will be Draw AF parallel to Since they have the same altitude , the line CD ...
Página 52
... altitude , or being situated between the same parallels , are equivalent . ( 44. ) PROBLEM . To find a triangle that shall be equivalent to a given polygon . Let ABCDF be the given polygon . Draw the diagonal CF , cutting off the ...
... altitude , or being situated between the same parallels , are equivalent . ( 44. ) PROBLEM . To find a triangle that shall be equivalent to a given polygon . Let ABCDF be the given polygon . Draw the diagonal CF , cutting off the ...
Página 53
... altitude ; then will the triangle be half the parallelogram . B For , draw the diagonal BD of the parallelogram , di- viding it into two equal parts , ( B. I , Prop . xxvII . ) Now , since the triangles ABF , ABD have the same base and ...
... altitude ; then will the triangle be half the parallelogram . B For , draw the diagonal BD of the parallelogram , di- viding it into two equal parts , ( B. I , Prop . xxvII . ) Now , since the triangles ABF , ABD have the same base and ...
Otras ediciones - Ver todas
Términos y frases comunes
a+b+c altitude angle ABC angle BAC angle BCD bisect centre chord circ circular sector circumference circumscribed polygon coincide cone consequently convex surface cylinder denote diagonal diameter dicular distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle figure formed given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC line AC line CD lines drawn measured by half meet multiplied number of sides parallel planes parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN point G prism PROBLEM produced Prop PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right-angled triangle Sabc Schol Scholium scribed semicircle semicircumference side AC similar similar triangles solid angle sphere spherical triangle square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII
Pasajes populares
Página 231 - THE sphere is a solid terminated by a curve surface, all the points of which are equally distant from a point within, called the centre.
Página 147 - PROBLEM. To inscribe a circle in a given triangle. Let ABC be the given triangle : it is required to inscribe a circle in the triangle ABC.
Página 17 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Página 28 - If two sides and the included angle of the one are respectively equal to two sides and the included angle of the other...
Página 233 - The volume of a cylinder is equal to the product of its base by its altitude. Let the volume of the cylinder be denoted by V, its base by B, and its altitude by H.
Página 276 - THEOREM. Two triangles on the same sphere, or on equal spheres, are equal in all their parts, when they have each an equal angle included between equal sides. Suppose the side...
Página 120 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Página 18 - If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another.
Página 232 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Página 96 - Similar figures, are those that have all the angles of the one equal to all the angles of the other, each to each, and the sides about the equal angles proportional.