Pure Mathematics, Volumen11874 |
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Resultados 1-5 de 73
Página 94
... PROOF . - Because the point A is the centre of the circle BCD , AC is equal to AB ( Def . 15 ) . Because the point B is the centre of the circle ACE , BC is equal to BA ( Def . 15 ) . Therefore AC and BC are each of them equal to AB ...
... PROOF . - Because the point A is the centre of the circle BCD , AC is equal to AB ( Def . 15 ) . Because the point B is the centre of the circle ACE , BC is equal to BA ( Def . 15 ) . Therefore AC and BC are each of them equal to AB ...
Página 95
... PROOF . - Because the point B is the centre of the circle CGH , BC is equal to BG ( Def . 15 ) . D quilateral . B as cen- tre . H Das cen- tre . G BC = BG . Because the point D is the centre of the circle GKL , DL DL = DG . is equal ...
... PROOF . - Because the point B is the centre of the circle CGH , BC is equal to BG ( Def . 15 ) . D quilateral . B as cen- tre . H Das cen- tre . G BC = BG . Because the point D is the centre of the circle GKL , DL DL = DG . is equal ...
Página 96
... PROOF . Because the point A is the centre of the circle AE = AD . DEF , AE is equal to AD ( Def . 15 ) . AD = C . AE and C each = AD . .. AE = C . AB = DE . AC = DF . 4 BAC = 4 EDF . But C is also equal to AD ( Construction ) ...
... PROOF . Because the point A is the centre of the circle AE = AD . DEF , AE is equal to AD ( Def . 15 ) . AD = C . AE and C each = AD . .. AE = C . AB = DE . AC = DF . 4 BAC = 4 EDF . But C is also equal to AD ( Construction ) ...
Página 97
... PROOF . For if the triangle ABC be applied to ( or placed Suppose upon ) the triangle DEF , A ABC put upon So that ... because AB is equal to DE ( Hypothesis ) . And AB coinciding with DE , AC shall coincide with DF , because the ...
... PROOF . For if the triangle ABC be applied to ( or placed Suppose upon ) the triangle DEF , A ABC put upon So that ... because AB is equal to DE ( Hypothesis ) . And AB coinciding with DE , AC shall coincide with DF , because the ...
Página 98
... PROOF . - Because AF is ( Construction ) , and AB is ( Hyp . ) , equal to AG equal to AC Therefore the two sides FA , AC are equal to the two sides GA , AB , each to each ; And they contain the angle FAG , common to the two triangles ...
... PROOF . - Because AF is ( Construction ) , and AB is ( Hyp . ) , equal to AG equal to AC Therefore the two sides FA , AC are equal to the two sides GA , AB , each to each ; And they contain the angle FAG , common to the two triangles ...
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Términos y frases comunes
a²b a²b² ab² ab³ ABCD algebraical angle ABC angle BAC angle BCD base BC BC is equal bisect brackets cent centim centre circle ABC circumference coefficient common Const cosec cube root decimal figures denominator divided divisor draw equation expression exterior angle factor Find the value fraction given straight line gnomon gram greater Hence integer join kilom less Let ABC logarithm metres miles millig Multiply opposite angles parallel parallelogram perpendicular PROOF.-Because Q. E. D. Proposition quotient ratio rectangle contained remainder right angles segment sides sin² sine square on AC square root subtraction touches the circle triangle ABC twice the rectangle x²y² x³y xy³
Pasajes populares
Página 272 - The angles in the same segment of a circle are equal to one another.
Página 103 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Página 233 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line. Let A and BC be two straight lines, and let BC be divided into any...
Página 112 - IF two triangles have two sides of the one equal to two sides of the...
Página 128 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 119 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles.
Página 113 - ... equal angles in each ; then shall the other sides be equal, each to each ; and also the third angle of the one to the third angle of the other.
Página 273 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.
Página 281 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Página 121 - THE straight lines which join the extremities of two equal and parallel straight lines, towards the same parts, are also themselves equal and parallel.