drop a Perpendicular from A to B, and the Triangle will be completed.

Note. The length of the two Legs may be found by

measuring them upon the same scale of equal parts from which the Hypothenuse was taken.

PROBLEM X. To make a Right Angled Triangle, the Angles and one Leg being given. Fig. 31.

Suppose the Angle at C 33o 15', and the Leg AC 285. Draw the Leg AC making it in length 285; at A erect a Perpendicular an indefinite length; at C make an Angle of 33o 15'; through where that number of Degrees cuts the Arch draw a Line till it meets the Perpendicular at B.

Note. If the given Line CA should not be so long as the Chord of 60°, it may be continued beyond A, for the purpose of making the Angle.

PROBLEM XI. To make a Right Angled Triangle, the Hypothenuse and one Leg being given. Fig. 32.

28.

Suppose the Hypothenuse AC 40, and the Leg AB

Draw the Leg AB in length 28; from B erect a Perpendicular an indefinite length; take 40 in the Dividers, and setting one foot in A, wherever the other foot strikes the Perpendicular will be the Point C.

Note. When the Triangle is constructed the Angles may be measured by a Protractor, or by a Scale of Chords.

PROBLEM XII. To make a Right Angled Triangle, the two Legs being given. Fig. 38.

Suppose the Leg AB 38, and the Leg BC 46.

Draw the Leg AB in length 38; from B erect a Perpendicular to C in length 46; and draw a Line from A to C.

PROBLEM XIII. To make an Oblique Angled Triangle, the Angles and one Side being given. Fig. 34.

Suppose the side BC 98; the Angle at B 45° 15', the Angle at D 108o 30', consequently the other Angle 26°

15'.

Draw the side BC in length 98; on the Point B make - an Angle of 45° 15'; on the Point C make an Angle of 26o 15', and draw the Lines BD and CD.

PROBLEM XIV.

To make an Oblique Angled Triangle, two Sides and an Angle opposite to one of them being given. Fig. 35.

Suppose the Side BC 160, the Side BD 79, and the Angle at C 29° 9'.

Draw the Side BC in length 160; at C make an Angle of 29° 9', and draw an indefinite Line through where the Degrees cut the Arch; take 79 in the Dividers, and with one foot in B lay the other on the Line CD; the point D will be the other Angle of the Triangle.

PROBLEM XV. To make an Oblique Angled Triangle, two Sides and their contained Angle being given. Fig. 36.

Suppose the Side BC 109, the Side BD 76, and the Angle at B 101° 30'.

Draw the Side BC in length 109; at B make an Angle of 101° 30', and draw the Side BD in length 76; draw a Line from D to C and it is done.

PBOBLEM XVI. To make a Square. PLATE II. Fig. 37.

Draw the Line AB the length of the proposed Square; from B erect a Perpendicular to C and make it of the same length as AB; from A and C, with the same distance in the Dividers, describe Arches intersecting each other at D, and draw the Lines AD and DC.

PROBLEM XVII. To make a Parallelogram. Fig. 38.

Draw the Line AB equal to the longest side of the Parallelogram; on B erect a Perpendicular the length of the shortest side to C; from C, with the longest Side, and from A, with the shortest Side, describe Arches in

tersecting each other at D, and draw the Lines AD and CD.

PROBLEM XVIII. To describe a Circle which shall pass through any three given Points, not lying in a Right Line, as A, B, D. Fig. 43.

Draw Lines from A to B and from B to D; bisect those Lines by PROBLEM II. and the Point where the bisecting Lines intersect each other, as at C, will be the Centre of the Circle.

PROBLEM XIX. To find the centre of a Circle.

By the last PROBLEM it is plain, that if three Points be any where taken in the given Circle's Periphery, the Centre of the Circle may be found as there taught.

Directions for constructing irregular Figures of four or more sides may be found in the following Treatise on SURVEYING.

TRIGONOMETRY.

TRIGONOMETRY is that part of practical GEOMETRY by which the Sides and Angles of Triangles are measured; whereby three things being given, either all Sides or Sides and Angles, a fourth may be found; either by measuring with a Scale and Dividers, according to the PROBLEMS in GEOMETRY, or more accurately by calculation with Logarithms, or with Natural Sines.

TRIGONOMETRY is divided into two Parts, Rectangular and Oblique-angular.

PART I.

RECTANGULAR TRIGONOMETRY.

This is founded on the following methods of applying a Triangle to a Circle.

PROPOSITION I. In every Right Angled Triangle, as ABC, PLATE II. Figure 44, it is plain from PLATE 1. Fig. 7. compared with the Geometrical Definitions to which that Figure refers, that if the Hypothenuse AC be made Radius, and with it an Arch of a Circle be described from each end, BC will be the Sine of the Angle at A, and AB the Sine of the Angle at C; that is, the Legs will be Sines of their opposite Angles.

PROPOSITION II. If one Leg, AB, Fig. 45, be made Radius, and with it on the Point A an Arch be de

scribed, then BC, the other Leg, will be the Tangent and AC the Secant of the Angle at A; and if BC be made Radius, and an Arch be described with it on the Point C, then AB will be the Tangent and AC the Secant of the Angle at C; that is, if one Leg be made Radius the other Leg will be a Tangent of its opposite Angle, and the Hypothenuse a Secant of the same Angle.

Thus, as different Sides are made Radius, the other Sides acquire different names, which are either Sines, Tangents or Secants.

As the Sides and Angles of Triangles bear a certain proportion to each other, two sides and one Angle, or one Side and two Angles being given, the other Sides or Angles may be found by instituting Proportions, according to the following Rules.

RULE I. To find a Side either of the Sides may be made Radius, then institute the following Proportion: As the name of the Side given, which will be either Radius, Sine, Tangent or Secant;

Is to the length of the Side given;

So is the name of the Side required, which also will be either Radius, Sine, Tangent or Secant;

To the length of the Side required.

RULE II. To find an Angle one of the given Sides must be made Radius, then institute the following Proportion;

As the length of the given side made Radius ;

Is to its name, that is Radius ;

So is the length of the other given Side;

To its name, which will be either Sine, Tangent or Secant.

Having instituted the Proportion, look the corresponding Logarithms, in the Logarithms for numbers for the length of the Sides, and in the Table of Artificial Sines, Tangents and Secants, for the Logarithmic Sine, Tangent or Secant.

Having found the Logarithms of the three given Terms, add together the Log. of the second and third Terms, and from their Sum subtract the Log. of the