 | Thomas Leybourn - 1814 - 420 páginas
...Hence, by adopting the notation in the question, we have But the sum of the angles of any polygon being equal to twice as many right angles as the polygon has sides, less four; the sum of all the angles of the polygon will be equal to an even number of right angles,... | |
 | John Radford Young - 1827 - 228 páginas
...to say, the sum of the angles of the polygon, together with those about the point within . it, are equal to twice as many right angles as the polygon has sides ; but those angles which are' about the point, amount to four right angles, (Prop. VI. Cor. 2.) deducting... | |
 | Adrien Marie Legendre - 1836 - 394 páginas
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles is equal to twice as many right angles as the polygon has sides. Again> the sum of all the interior . angles is equal to two.right angles, taken as many times, less... | |
 | William Scott - 1845 - 288 páginas
...and end ought to coincide. Also, the sum of all the angles, together with four right angles, ought to be equal to twice as many right angles as the polygon has sides (Eue. i. 32. cor.). To find the angle contained by two straight lines conceived to be drawn from a... | |
 | Nathan Scholfield - 1845 - 894 páginas
...figure has sides, wanting four right angles. Hence, the interior angles plus four right angles, is equal to twice as many right angles as the polygon has sides, and consequently, equal to the sum of the interior angles plus the exterior angles. Taking from each... | |
 | Sir J. Butler Williams - 1846 - 368 páginas
...sum of all the interior angles of the polygon formed by joining the stations by straight lines will be equal to twice as many right angles as the polygon has sides, wanting 4 right angles (Euc. Cor. 32, I.) Thus, if the figure have 3 sides, the sum of the interior... | |
 | George Roberts Perkins - 1847 - 326 páginas
...angles is equal to four right angles (Prop. xxm) ; therefore the sum of all the interior angles is equal to twice as many right angles as the polygon has sides, wanting four right angles. Cor. 1. Jn any triangle, the sum of all the three angles is equal to two... | |
 | Elias Loomis - 1849 - 252 páginas
...equal to two right angles (Prop. XXVII.); therefore the sum of the angles of all the triangles, is equal to twice as many right angles as the polygon has sides. But the same angles are equal to the angles of the polygon, together with the angles at the point F,... | |
 | Charles Davies - 1849 - 372 páginas
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles is equal to twice as many right angles as the polygon has sides. Again, the sum of all tho interior angles is equal to two right angles, taken as many times, less two,... | |
 | Charles Davies - 1850 - 238 páginas
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles will be equal to twice as many right angles as the polygon has sides. But the sum of all the interior angles together with four right angles, is equal to twice as many right... | |
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... is equal to twice as many right angles as the polygon 
