Daboll's Complete Schoolmaster's Assistant Being a Plain Comprehensive System of Practical Arithmetic

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Bolles and Williams, 1843 - 240 páginas
 

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Página 195 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Página 167 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator; and they will form the fraction required.
Página 183 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Página 106 - Let the farthings in the given pence and farthings possess the second and third places ; observing to increase the second place or place of hundredths, by 6 if the shillings be odd ; and the third place by 1 "when the farthings exceed 12, and by 2 when they exceed 36. EXAMPLES. 1. Find the decimal of 7s. 9fd. by inspection. ,3 =4 6s. 5 for the odd shillings. 39=the farthings in 9|d. 2 for the excess of 36. £. ,391=dechnal required'.
Página 90 - To reduce an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Página 233 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Página 44 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.
Página 126 - ... multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term.
Página 119 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Página 205 - ... the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms.

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