Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's and Playfair's Editions ...Collins, Brother & Company, 1846 - 138 páginas |
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Página 8
... unequal . 26. An acute - angled triangle has its three angles acute . 27. A right - angled triangle has one right angle . 28. An obtuse - angled triangle has one obtuse angle . 29. Quadrilateral figures , or quadrangles , are contained ...
... unequal . 26. An acute - angled triangle has its three angles acute . 27. A right - angled triangle has one right angle . 28. An obtuse - angled triangle has one obtuse angle . 29. Quadrilateral figures , or quadrangles , are contained ...
Página 9
... unequal . Also , the perimeters of regular polygons being equal , that perimeter which has the greater number of ... unequal . 5. Take equals from unequals , the remainders will be unequal . 6. Doubles of the same are equal to each other ...
... unequal . Also , the perimeters of regular polygons being equal , that perimeter which has the greater number of ... unequal . 5. Take equals from unequals , the remainders will be unequal . 6. Doubles of the same are equal to each other ...
Página 16
... unequal , which is impossible , ( b ) : A therefore the lines ABC , ABD , which have the cominon segment AB , are not both straight lines . Recite ( a ) , p . 11 ; ( b ) , ax . 10 . Q. E. D. 12 P. To draw a straight line ( CH ) ...
... unequal , which is impossible , ( b ) : A therefore the lines ABC , ABD , which have the cominon segment AB , are not both straight lines . Recite ( a ) , p . 11 ; ( b ) , ax . 10 . Q. E. D. 12 P. To draw a straight line ( CH ) ...
Página 20
... unequal ; the base ( EF ) oppo- site the less angle ( D ) is less than the base ( BC ) opposite the greater angle ( A ) . Constr . Let DF be not less than DE : then , at the point D. in the straight line ED , make the angle EDG equal to ...
... unequal ; the base ( EF ) oppo- site the less angle ( D ) is less than the base ( BC ) opposite the greater angle ( A ) . Constr . Let DF be not less than DE : then , at the point D. in the straight line ED , make the angle EDG equal to ...
Página 32
... unequal , the figure is an oblong ; and in either case , it is a right angled parallelogram . - H C 2. A gnomon is the sum of the two com- plements ( p . 43 , ) and one of the parallelo- B grams about the diameter of a rectangle . NOTE ...
... unequal , the figure is an oblong ; and in either case , it is a right angled parallelogram . - H C 2. A gnomon is the sum of the two com- plements ( p . 43 , ) and one of the parallelo- B grams about the diameter of a rectangle . NOTE ...
Otras ediciones - Ver todas
Euclid's Elements, Or Second Lessons in Geometry, in the Order of Simson's ... D. M'Curdy Sin vista previa disponible - 2017 |
Euclid's Elements, Or Second Lessons in Geometry, in the Order of Simson's ... D. M'Curdy Sin vista previa disponible - 2017 |
Términos y frases comunes
ABCD alternate angles angle ACD angles ABC angles equal antecedents Argument base BC bisected centre Chart chord circle ABC circumference Constr Denison Olmsted diameter draw drawn equal angles equal arcs equal radii equal sides equals the squares equi equiangular equilateral equilateral polygon equimultiples exterior angle fore Geometry given circle given rectilineal given straight line gles gnomon greater half inscribed isosceles isosceles triangle join less meet multiple opposite angles parallelogram parallelopipeds pentagon perimeter perpendicular plane polygon produced propositions Q. E. D. Recite radius ratio rectangle rectilineal figure School segment semicircle similar similar triangles sine square of AC tangent touches the circle triangle ABC unequal Wherefore
Pasajes populares
Página 90 - If two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals, the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Página 117 - In the same way it may be proved that a : b : : sin. A : sin. B, and these two proportions may be written a : 6 : c : : sin. A : sin. B : sin. C. THEOREM III. t8. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference. By Theorem II. we have a : b : : sin. A : sin. B.
Página 92 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.
Página 79 - THEOREM. lf the first has to the second the same ratio which the third has to the fourth, but the third to the fourth, a greater ratio than the fifth has to the sixth ; the first shall also have to the second a greater ratio than the fifth, has to the sixth.
Página 87 - If a straight line be drawn parallel to one of the sides of a triangle, it shall cut the other sides, or those sides produced, proportionally...
Página 26 - Triangles upon equal bases, and between the same parallels, are equal to one another.
Página 94 - Equal parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles reciprocally proportional ; and parallelograms that have one angle of the one equal to one angle of the other, and their sides about the equal angles reciprocally proportional, are equal to one another.
Página 12 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Página 133 - If a straight line stand at right angles to each of two straight lines at the point of their intersection, it shall also be at right angles to the plane which passes through them, that is, to the plane in which they are.
Página 13 - AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle DBC is equal to the angle ACB; therefore the base DC is equal to the base AB, and the triangle DBC is< equal to the triangle (4. 1.) ACB, the less to 'the greater; which is absurd.