The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry, from the Edition of Dr. Robert Simson ... With ExercisesCharles Henry Law, 1854 - 120 páginas |
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Página 7
... given finite straight line . Let AB be the given straight line ; it is required to describe an equi- lateral ... point C , in which the circles cut one another , draw ( Post . 1. ) the straight lines CA , CB , to the points 4 , B ; ABC shall ...
... given finite straight line . Let AB be the given straight line ; it is required to describe an equi- lateral ... point C , in which the circles cut one another , draw ( Post . 1. ) the straight lines CA , CB , to the points 4 , B ; ABC shall ...
Página 8
... given point A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III . - PROBLEM . From the greater of two given straight lines to cut off a part equal to the less . Let AB and C be the two ...
... given point A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III . - PROBLEM . From the greater of two given straight lines to cut off a part equal to the less . Let AB and C be the two ...
Página 13
... a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle , it is required to bisect it . Take any point Din AB , and from AC cut ( I. 3. ) off AE equal to AD ; join DE , and upon ...
... a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle , it is required to bisect it . Take any point Din AB , and from AC cut ( I. 3. ) off AE equal to AD ; join DE , and upon ...
Página 14
... given finite straight line , that is , to divide it into two equal parts ... point D. C A. D B Because AC is equal to CB , and CD common to the two ... point D. Which was to be done . PROP . XI.- -- PROBLEM . To draw a straight line at ...
... given finite straight line , that is , to divide it into two equal parts ... point D. C A. D B Because AC is equal to CB , and CD common to the two ... point D. Which was to be done . PROP . XI.- -- PROBLEM . To draw a straight line at ...
Página 15
Euclid, Samuel A. GOOD. straight line FC drawn from the given point C ' is at right angles to the given straight line AB F A D C E B Because DC is equal to CE , and FC common to the two triangles DCF , ECF ; 1 . The two sides DC , CF ...
Euclid, Samuel A. GOOD. straight line FC drawn from the given point C ' is at right angles to the given straight line AB F A D C E B Because DC is equal to CE , and FC common to the two triangles DCF , ECF ; 1 . The two sides DC , CF ...
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Términos y frases comunes
AB is equal AC is equal adjacent angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angle equal base BC bisected circle ABC circumference diameter double draw equal angles equal Constr equal Hyp equal straight lines equal to BC equilateral and equiangular EUCLID'S ELEMENTS exterior angle given circle given point given rectilineal angle given straight line given triangle gnomon greater inscribed interior and opposite less Let ABC Let the straight likewise opposite angles parallel to CD parallelogram pentagon perpendicular point F produced Q.E.D. PROP rectangle AE rectangle contained remaining angle required to describe right angles semicircle side BC square of AC straight line AB straight line AC straight line drawn touches the circle triangle ABC twice the rectangle