The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Página 7
To describe an equilateral triangle upon a given finite straight line . Let AB be the given straight line ; it is required to describe an equilateral triangle upon it . From the centre A , at the distance AB , describe ( Postulate 3. ) ...
To describe an equilateral triangle upon a given finite straight line . Let AB be the given straight line ; it is required to describe an equilateral triangle upon it . From the centre A , at the distance AB , describe ( Postulate 3. ) ...
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Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III . - PROBLEM , From the greater of two given straight lines to cut off a part equal to the less .
Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III . - PROBLEM , From the greater of two given straight lines to cut off a part equal to the less .
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EUCLID., Samuel A. GOOD ... D G А F B For if the triangle ABC be applied to DEF , so that the point B be on E , and the straight line BC upon EF ... To bisect a given rectilineal angle , that is , to divide it into troo equal angles .
EUCLID., Samuel A. GOOD ... D G А F B For if the triangle ABC be applied to DEF , so that the point B be on E , and the straight line BC upon EF ... To bisect a given rectilineal angle , that is , to divide it into troo equal angles .
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The angle BAC is bisected by the straight line AF . Which was to be done . PROP . X. -PROBLEM . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to ...
The angle BAC is bisected by the straight line AF . Which was to be done . PROP . X. -PROBLEM . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to ...
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straight line FC drawn from the given point C is at right angles to the given straight line AB E B A D Because DC is equal to CE , and FC common to the two triangles DCF , ECF ; 1 . The two sides DC , CF , are equal to the two EC ...
straight line FC drawn from the given point C is at right angles to the given straight line AB E B A D Because DC is equal to CE , and FC common to the two triangles DCF , ECF ; 1 . The two sides DC , CF , are equal to the two EC ...
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Términos y frases comunes
AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole
Información bibliográfica
| Título | The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
| Autores | EUCLID., Samuel A. GOOD |
| Edición | 2 |
| Editor | Charles Henry Law, 1854 |
| Procedencia del original | Biblioteca Británica |
| Digitalizado | 10 Dic. 2013 |
| Largo | 120 páginas |
| Exportar cita | BiBTeX EndNote RefMan |