The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Página 10
to AF , the less , and join FC , GB . Because ÅF is equal ( Constr . ) to AG , and AB ( Hypothesis ) to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the angle FAG common to the two triangles ...
to AF , the less , and join FC , GB . Because ÅF is equal ( Constr . ) to AG , and AB ( Hypothesis ) to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the angle FAG common to the two triangles ...
Página 11
A D B For if AB be not equal to 4C , one of them is greater than the other . Let AB be the greater , and from it cut off ( I. 3. ) DB equal to AC , the less , and join DC . Therefore because in the triangles DBC , ACB , DB is equal to ...
A D B For if AB be not equal to 4C , one of them is greater than the other . Let AB be the greater , and from it cut off ( I. 3. ) DB equal to AC , the less , and join DC . Therefore because in the triangles DBC , ACB , DB is equal to ...
Página 12
terminated in the extremity A of the base equal to one another , and likewise their sides CB , DB , that are terminated in B. E C A B A. B Join CD . Then , in the case in which the vertex of each of the triangles is without the other ...
terminated in the extremity A of the base equal to one another , and likewise their sides CB , DB , that are terminated in B. E C A B A. B Join CD . Then , in the case in which the vertex of each of the triangles is without the other ...
Página 13
off AE equal to AD ; join DE , and upon it , on the side remote from 4 , describe ( I. 1. ) an equilateral triangle DEF ; then join AF ; the straight line AF bisects the triangle BAC . A D F B Because AD is equal to AE , and AF is ...
off AE equal to AD ; join DE , and upon it , on the side remote from 4 , describe ( I. 1. ) an equilateral triangle DEF ; then join AF ; the straight line AF bisects the triangle BAC . A D F B Because AD is equal to AE , and AF is ...
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... at right angles to AB . Take any point D in Ac , and ( I. 3. ) make CE equal to CD , and upon DE describe ( I. 1. ) the equilateral triangle DFE , and join FC ; the straight line FC drawn from the given point C is 14 EUCLID'S ELEMENTS .
... at right angles to AB . Take any point D in Ac , and ( I. 3. ) make CE equal to CD , and upon DE describe ( I. 1. ) the equilateral triangle DFE , and join FC ; the straight line FC drawn from the given point C is 14 EUCLID'S ELEMENTS .
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole
Información bibliográfica
| Título | The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
| Autores | EUCLID., Samuel A. GOOD |
| Edición | 2 |
| Editor | Charles Henry Law, 1854 |
| Procedencia del original | Biblioteca Británica |
| Digitalizado | 10 Dic. 2013 |
| Largo | 120 páginas |
| Exportar cita | BiBTeX EndNote RefMan |