The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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In this edition , it is endeavoured , by a new , yet extremely simple , typographical arrangement , to render the text of Euclid more perspicuous than when printed in the ordinary manner , and to make it , as it were , its own ...
In this edition , it is endeavoured , by a new , yet extremely simple , typographical arrangement , to render the text of Euclid more perspicuous than when printed in the ordinary manner , and to make it , as it were , its own ...
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The angle CBE is equal to the angle EBA ; in the same manner , because ABD is a straight line , 2 . The angle DBE is equal to the angle EBA ; wherefore ( As . 1. ) 3 . The angle DBE is equal to the angle CBE , the less to the greater ...
The angle CBE is equal to the angle EBA ; in the same manner , because ABD is a straight line , 2 . The angle DBE is equal to the angle EBA ; wherefore ( As . 1. ) 3 . The angle DBE is equal to the angle CBE , the less to the greater ...
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And in like manner it may be demonstrated that no other can be in the same straight line with it but BD , therefore 5 . BD is in the same straight line with CB . Wherefore , if at a point , & c . Q.E.D. PROP . XV . - THEOREM .
And in like manner it may be demonstrated that no other can be in the same straight line with it but BD , therefore 5 . BD is in the same straight line with CB . Wherefore , if at a point , & c . Q.E.D. PROP . XV . - THEOREM .
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In the same manner it can be demonstrated that 5 . The angles CEB , 4ED , are equal . Therefore , if two straight lines , & c . Q.E.D. Cor . 1. - From this it is manifest , that , if two straight lines cut one another , the angles they ...
In the same manner it can be demonstrated that 5 . The angles CEB , 4ED , are equal . Therefore , if two straight lines , & c . Q.E.D. Cor . 1. - From this it is manifest , that , if two straight lines cut one another , the angles they ...
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In like manner , it may be demonstrated , that 5 . BAC , ACB , as also CAB , ABC , are less than two right angles . Therefore any two angles , & c . Q.E.D. PROP . XVIII . - THEOREM . The greater side of every triangle is opposite to the ...
In like manner , it may be demonstrated , that 5 . BAC , ACB , as also CAB , ABC , are less than two right angles . Therefore any two angles , & c . Q.E.D. PROP . XVIII . - THEOREM . The greater side of every triangle is opposite to the ...
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole