The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Página 9
The whole triangle ABC shall coincide with the whole triangle DEF and be equal to it ; and the other angles of the one shall coincide with the remaining angles of the other , and be equal to them , viz . 6 . The angle ABC shall be equal ...
The whole triangle ABC shall coincide with the whole triangle DEF and be equal to it ; and the other angles of the one shall coincide with the remaining angles of the other , and be equal to them , viz . 6 . The angle ABC shall be equal ...
Página 10
The triangles BFC , CGB , are equal , and their remaining angles are equal , each to each , to which the equal sides are opposite ; therefore 5 . The angle FBC is equal to the angle GCB , and the angle BCF to the angle CBG .
The triangles BFC , CGB , are equal , and their remaining angles are equal , each to each , to which the equal sides are opposite ; therefore 5 . The angle FBC is equal to the angle GCB , and the angle BCF to the angle CBG .
Página 18
same straight line with it ; therefore , because the straight line AB makes angles with the straight line CBE , upon one ... The remaining angle ABE is equal to the remaining angle ABD , the less to the greater , which is impossible ...
same straight line with it ; therefore , because the straight line AB makes angles with the straight line CBE , upon one ... The remaining angle ABE is equal to the remaining angle ABD , the less to the greater , which is impossible ...
Página 19
Take away the common angle AED , and ( Ax . 3. ) 4 . The remaining angle CEA is equal to the remaining angle DEB . In the same manner it can be demonstrated that 5 . The angles CEB , 4ED , are equal . Therefore , if two straight lines ...
Take away the common angle AED , and ( Ax . 3. ) 4 . The remaining angle CEA is equal to the remaining angle DEB . In the same manner it can be demonstrated that 5 . The angles CEB , 4ED , are equal . Therefore , if two straight lines ...
Página 29
Take away the common angle BGH ; therefore 2 . The remaining angle AGH is equal to the remaining angle GHD , and they are alternate angles ; therefore ( I. 27. ) 3 . AB is parallel to CD . Wherefore if a straight line , & c .
Take away the common angle BGH ; therefore 2 . The remaining angle AGH is equal to the remaining angle GHD , and they are alternate angles ; therefore ( I. 27. ) 3 . AB is parallel to CD . Wherefore if a straight line , & c .
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole
Información bibliográfica
| Título | The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
| Autores | EUCLID., Samuel A. GOOD |
| Edición | 2 |
| Editor | Charles Henry Law, 1854 |
| Procedencia del original | Biblioteca Británica |
| Digitalizado | 10 Dic. 2013 |
| Largo | 120 páginas |
| Exportar cita | BiBTeX EndNote RefMan |