A Text-book of GeometryGinn, 1888 - 386 páginas |
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Página 3
... ABCD move to the right to the position EFGH . points A , B , C , and D will generate the lines AE , BF , CG , and DH . respectively . The lines AB , BC , CD , and AD will generate the sur- faces AF , BG , CH , and AH , respectively ...
... ABCD move to the right to the position EFGH . points A , B , C , and D will generate the lines AE , BF , CG , and DH . respectively . The lines AB , BC , CD , and AD will generate the sur- faces AF , BG , CH , and AH , respectively ...
Página 62
... ABCD and A'B'C'D ' , A'B ' , AD = A'D ' , and △ A = △ A ' . To prove that the [ $ ] are equal . Apply □ ABCD to □ A'B'C'D ' , so that AD wi and coincide with A'D ' . Then AB will fall on A'B ' , ( for A = A ' , by hyp . ) , and the ...
... ABCD and A'B'C'D ' , A'B ' , AD = A'D ' , and △ A = △ A ' . To prove that the [ $ ] are equal . Apply □ ABCD to □ A'B'C'D ' , so that AD wi and coincide with A'D ' . Then AB will fall on A'B ' , ( for A = A ' , by hyp . ) , and the ...
Página 70
... ABCD be a quadrilateral , having AB = CB = CD , and having the diagonals AC and BD To prove that the diagonal AC is an axis of symm is to the diagonal BD . Proof . In the AABC and ADC and AB AD , and BC = DC , = AC AC . ..A ABC- Δ ADC ...
... ABCD be a quadrilateral , having AB = CB = CD , and having the diagonals AC and BD To prove that the diagonal AC is an axis of symm is to the diagonal BD . Proof . In the AABC and ADC and AB AD , and BC = DC , = AC AC . ..A ABC- Δ ADC ...
Página 73
... equal . 67. If the diagonals of a trapezoid are equal , the trapezoid is isosceles . C D HINT . Draw CE and DF 1 to CD . Show that A ADF and BCE are equal , that A COD and AOB are 1 DOD 10 68. ABCD is a parallelogram , E and F.
... equal . 67. If the diagonals of a trapezoid are equal , the trapezoid is isosceles . C D HINT . Draw CE and DF 1 to CD . Show that A ADF and BCE are equal , that A COD and AOB are 1 DOD 10 68. ABCD is a parallelogram , E and F.
Página 74
George Albert Wentworth. 10 68. ABCD is a parallelogram , E and F the middle points BC respectively ; show that BE and DF will trisect the diag 69. If from the diagonal BD of a square ABCD , BE is cu to BC , and EF is drawn perpendicular ...
George Albert Wentworth. 10 68. ABCD is a parallelogram , E and F the middle points BC respectively ; show that BE and DF will trisect the diag 69. If from the diagonal BD of a square ABCD , BE is cu to BC , and EF is drawn perpendicular ...
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Términos y frases comunes
AB² ABCD AC² acute angle adjacent angles altitude angle formed angles are equal base bisector bisects called centre chord circumference circumscribed coincide construct a square decagon diagonals diameter Draw equal respectively equiangular equiangular polygon equidistant equilateral polygon equilateral triangle exterior angle feet figure Find the area given circle given line given point given straight line given triangle greater Hence homologous sides hypotenuse inches intersecting isosceles triangle legs length line drawn line joining measured by arc middle points number of sides obtuse opposite sides parallel parallelogram perimeter perpendicular PROPOSITION prove Proof quadrilateral radii ratio rectangle regular inscribed regular polygon rhombus right angle right triangle SCHOLIUM secant segments similar polygons square equivalent straight angle subtended tangent THEOREM third side trapezoid triangle ABC triangle is equal vertex vertices
Pasajes populares
Página 46 - If two triangles have two sides of one equal, respectively, to two sides of the other, but the included angle of the first greater than the included angle of the second, the third side of the first is greater than the third side of the second...
Página 69 - The exterior angles of a polygon, made by producing each of its sides in succession, are together equal to four right angles.
Página 187 - Two triangles having an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles.
Página 64 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.
Página 201 - To construct a parallelogram equivalent to a given square, and having the sum of its base and altitude equal to a given line.
Página 215 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Página 161 - In any triangle, the square of the side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other upon that side.
Página 135 - In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent.
Página 156 - If in a right triangle a perpendicular is drawn from the vertex of the right angle to the hypotenuse : I.
Página 15 - LET it be granted that a straight line may be drawn from any one point to any other point. 2. That a terminated straight line may be produced to any length in a straight line. 3.