Proceedings of the Edinburgh Mathematical Society, Volúmenes1-2Scottish Academic Press, 1894 |
Dentro del libro
Resultados 1-5 de 28
Página 13
... bisects AB and AL , Because therefore Similarly therefore therefore This theorem may C'G is parallel to BL . B'G ,, 99 99 CL ; BLCG is a parallelogram ; A ' is the mid point of BC . be proved in many other ways . DEF . The point G is ...
... bisects AB and AL , Because therefore Similarly therefore therefore This theorem may C'G is parallel to BL . B'G ,, 99 99 CL ; BLCG is a parallelogram ; A ' is the mid point of BC . be proved in many other ways . DEF . The point G is ...
Página 17
... Bisect BC in A ' , and divide AA ' at G so that AG : A'G 2 : 1 . = In this case the sum of the distances from the centroid of the points on one side of it is equal to the distance from the centroid of the point on the opposite side ...
... Bisect BC in A ' , and divide AA ' at G so that AG : A'G 2 : 1 . = In this case the sum of the distances from the centroid of the points on one side of it is equal to the distance from the centroid of the point on the opposite side ...
Página 24
... bisect each other at E. Now if A ' be the mid point of BC , it will also be the mid point of DA1 ; therefore AA ' , AE , two medians of triangle ADA1 , intersect at a point G such that AG = 2A'G and A1G = 2EG . Hence since AA ' , AE are ...
... bisect each other at E. Now if A ' be the mid point of BC , it will also be the mid point of DA1 ; therefore AA ' , AE , two medians of triangle ADA1 , intersect at a point G such that AG = 2A'G and A1G = 2EG . Hence since AA ' , AE are ...
Página 33
... bisects AB and AC . Similarly for the circles on OB and OC . ( 4 ) If the circle on OA as diameter should cut BC at P and P ' , then AP is a mean proportional † between BP and CP , and AP ' is a mean proportional between BP ' and CP ...
... bisects AB and AC . Similarly for the circles on OB and OC . ( 4 ) If the circle on OA as diameter should cut BC at P and P ' , then AP is a mean proportional † between BP and CP , and AP ' is a mean proportional between BP ' and CP ...
Página 37
... the mid points of BO , CO . Then the right - angled triangles OVO1 , OWO , have two sides of the one equal to two sides of the other ; therefore OO , bisects 0,0,0 . Similarly for OO2 , 003 . ( 22. ) If 001 , 002 , 003 be Sect . I. 37.
... the mid points of BO , CO . Then the right - angled triangles OVO1 , OWO , have two sides of the one equal to two sides of the other ; therefore OO , bisects 0,0,0 . Similarly for OO2 , 003 . ( 22. ) If 001 , 002 , 003 be Sect . I. 37.
Otras ediciones - Ver todas
Proceedings of the Edinburgh Mathematical Society Edinburgh Mathematical Society Vista completa - 1966 |
Términos y frases comunes
2abcA a+b+c A₁ B₁ bisects centroid circle circumcentre circumcircle circumscribed collinear complementary triangle concyclic congruent conic contour-lines curve D₁ denoted diagonal diameter double point draw drawn Edinburgh Mathematical Society enantiomorph equal excentres excircle FIGURE formed by joining four triangles fundamental triangle Gentleman's Diary Geometry George Watson's College given H₁ Hence incentre incircle inscribed internal bisector intersect Lady's and Gentleman's m₁ Mathematical Master Mathématiques medians meet the circumcircle mid point nine-point circle oppositely situated orthic triangle orthocentre pairs parallel to BC parallelogram passes perpendicular to BC plane point of BC polar Professor proof properties Proposition quadrilateral r₁ radii radius respectively rhombi right angles semiperimeter similar Similarly spherical tangents tartaric acid temperature theorem THOMAS MUIR triangle ABC triangle formed vertex vertices
Pasajes populares
Página 52 - The diagonals of a quadrilateral intersect at right angles. Prove that the sum of the squares on one pair of opposite sides is equal to the sum of the squares on the other pair.
Página 11 - Any two sides of a triangle are together greater than the third side.
Página 47 - The six straight lines. joining two and two the centres of the four circles which touch the sides of a triangle pass each through one of the vertices of the triangle.
Página 15 - The perpendiculars from the vertices of a triangle on the opposite sides are concurrent.
Página 34 - Compare the area of the triangle formed by joining the centres of these squares with the area of the equilateral triangle.
Página 11 - The opposite angles of a quadrilateral inscribed in a circle are together equal to two right angles, with converse.
Página 37 - If two triangles have two sides of the one equal to two sides of the...
Página 14 - Wherefore, if the ratios &c. EXERCISES. 1. Shew that the locus of the middle points of straight lines parallel to the base of a triangle and terminated by its sides is a straight line. 2. CAB, CEB are two triangles having the angle B common and the sides CA, CE equal ; if BAE be produced to D and ED be taken a third proportional to BA , AC, then the triangle BDC is similar to the triangle BAC.
Página 8 - The straight line, joining the points of bisection of two sides of a triangle, is parallel to the base.
Página 62 - If the perpendicular from any vertex of a triangle to the opposite side divides that side into two segments, how does each of these segments compare in length with its adjacent side of the triangle ? Prove it.