Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 páginas |
Dentro del libro
Resultados 1-3 de 87
Página 116
... base BC , is to the base CD , so is the triangle ABC to the triangle ACD , and the parallelogram EC to the parallelogram CF. EA F Produce BD both ways to the points H , L , and take any number of straight lines BG , GH , each equal to ...
... base BC , is to the base CD , so is the triangle ABC to the triangle ACD , and the parallelogram EC to the parallelogram CF. EA F Produce BD both ways to the points H , L , and take any number of straight lines BG , GH , each equal to ...
Página 196
... base CD to the base LQ ; so is the solid CF to the solid LR ; but as the base AB to the base LQ , so the base CD to the base LQ , as has been proved : therefore as the solid AE to the solid LR , so is the solid CF to the solid LR ; and ...
... base CD to the base LQ ; so is the solid CF to the solid LR ; but as the base AB to the base LQ , so the base CD to the base LQ , as has been proved : therefore as the solid AE to the solid LR , so is the solid CF to the solid LR ; and ...
Página 197
... bases . Let AB , CD be solid parallelopipeds of the same altitude ; they are to one another as their bases ; that is , as the base AE to the base CF , so is the solid AB to the solid CD . To the straight line - FG apply the ...
... bases . Let AB , CD be solid parallelopipeds of the same altitude ; they are to one another as their bases ; that is , as the base AE to the base CF , so is the solid AB to the solid CD . To the straight line - FG apply the ...
Otras ediciones - Ver todas
Términos y frases comunes
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore