Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 páginas |
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Página 9
... coincides with the point E ; wherefore the base BC shall coincide with the base EF ( cor . def . 3. ) , and shall be equal to it . Therefore also the whole triangle ABC shall coincide with the whole triangle DEF , so that the spaces ...
... coincides with the point E ; wherefore the base BC shall coincide with the base EF ( cor . def . 3. ) , and shall be equal to it . Therefore also the whole triangle ABC shall coincide with the whole triangle DEF , so that the spaces ...
Página 72
... coincide with the point D , be- cause AB is equal to CD : Therefore the straight line AB coinciding with CD , A E BC F D the segment AEB must ( 23. 3. ) coincide with the segment CFD , and therefore is equal to it . PROP . XXV . THEOR ...
... coincide with the point D , be- cause AB is equal to CD : Therefore the straight line AB coinciding with CD , A E BC F D the segment AEB must ( 23. 3. ) coincide with the segment CFD , and therefore is equal to it . PROP . XXV . THEOR ...
Página 191
... coincide with it , because they are similar and equal ( 8. Ax . 1. ) , and because their equal sides KN and AD coincide . And in the same manner it is shewn that the other planes of the solid KQ coincide with the other planes of the ...
... coincide with it , because they are similar and equal ( 8. Ax . 1. ) , and because their equal sides KN and AD coincide . And in the same manner it is shewn that the other planes of the solid KQ coincide with the other planes of the ...
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Términos y frases comunes
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore