Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 páginas |
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Página 90
... reason , BC , CD are each of them equal to BA or AD ; therefore the quadrilateral figure ABCD is equilateral . It B is also rectangular ; for the straight line BD being a diameter of the circle ABCD , BAD is a semicircle ; wherefore the ...
... reason , BC , CD are each of them equal to BA or AD ; therefore the quadrilateral figure ABCD is equilateral . It B is also rectangular ; for the straight line BD being a diameter of the circle ABCD , BAD is a semicircle ; wherefore the ...
Página 129
... reason , the angle ABH is equal to the angle CDE ; also the angle at A is equal to the angle at C , and the angle GHB to FED ; There- fore the rectilineal figure ABHC is equiangular to CDEF : but likewise these figures have their sides ...
... reason , the angle ABH is equal to the angle CDE ; also the angle at A is equal to the angle at C , and the angle GHB to FED ; There- fore the rectilineal figure ABHC is equiangular to CDEF : but likewise these figures have their sides ...
Página 306
... REASON . For it was shewn , that the pyra- mids DABE and DACE are concluded to be equal , because each of them is determined to be of a certain magnitude , rather than of any other , by conditions that are the same in both , so that ...
... REASON . For it was shewn , that the pyra- mids DABE and DACE are concluded to be equal , because each of them is determined to be of a certain magnitude , rather than of any other , by conditions that are the same in both , so that ...
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Términos y frases comunes
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore