Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 páginas |
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Página 23
... angle ACD is equal to the two interior and opposite angles CAB , ABC ; to these angles add the angle ACB , and the angles ACD , ACB are equal to the three angles CBA , BAC , ACB ; but the angles ACD , ACB are equal ( 6. 1. ) to two right ...
... angle ACD is equal to the two interior and opposite angles CAB , ABC ; to these angles add the angle ACB , and the angles ACD , ACB are equal to the three angles CBA , BAC , ACB ; but the angles ACD , ACB are equal ( 6. 1. ) to two right ...
Página 24
... right angles as the figure has sides , wanting four . COR . 1. All the exterior angles of any rectilineal figure are together equal to four right angles . Because every interior an- gle ABC , with its adjacent exterior ABD , is equal ...
... right angles as the figure has sides , wanting four . COR . 1. All the exterior angles of any rectilineal figure are together equal to four right angles . Because every interior an- gle ABC , with its adjacent exterior ABD , is equal ...
Página 51
... angles CEB , EBC is half a right angle ; and therefore the whole AEB is a right angle ; And because the angle GEF is half a right angle , and EGF a right angle , for it is equal ( 21. 1. ) to the interior and opposite angle ECB , the ...
... angles CEB , EBC is half a right angle ; and therefore the whole AEB is a right angle ; And because the angle GEF is half a right angle , and EGF a right angle , for it is equal ( 21. 1. ) to the interior and opposite angle ECB , the ...
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Términos y frases comunes
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore