Principles and Applications of Mathematics for Communications-electronicsHeadquarters, Department of the Army, 1992 |
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Página 14
... flowing through a resistor can be determined by taking the square root of the quotient obtained by divid- ing the value of power supplied to the resistor ( in watts ) by the value of the resistance ( in 26. General a . Algebra is an ...
... flowing through a resistor can be determined by taking the square root of the quotient obtained by divid- ing the value of power supplied to the resistor ( in watts ) by the value of the resistance ( in 26. General a . Algebra is an ...
Página 127
... flows through the branch of less resistance , and the smaller fraction of current flows through the branch of greater resistance . The two parts of the current join again upon leaving the re- sistors . a . The total current ( I , ) in a ...
... flows through the branch of less resistance , and the smaller fraction of current flows through the branch of greater resistance . The two parts of the current join again upon leaving the re- sistors . a . The total current ( I , ) in a ...
Página 132
... flowing away from a point as there is flowing to it . The second law simply means that the voltage source is equal to the sum of the voltage drops around any closed circuit . For example , start- ing at point X ( fig . 65 ) and going ...
... flowing away from a point as there is flowing to it . The second law simply means that the voltage source is equal to the sum of the voltage drops around any closed circuit . For example , start- ing at point X ( fig . 65 ) and going ...
Página 133
... flowing through the 6 - ohm resistor plus the current 12 flowing through the 7- and 8 - ohm resistors equals the current I1 + 12 flowing through the remainder of the circuit , which includes the 5 - ohm resistor . Considering the first ...
... flowing through the 6 - ohm resistor plus the current 12 flowing through the 7- and 8 - ohm resistors equals the current I1 + 12 flowing through the remainder of the circuit , which includes the 5 - ohm resistor . Considering the first ...
Página 134
... flows through it . PI2R = 52 X 50 = 1,250 watts Example 2 : Find the power delivered by a 12 - volt battery when the cur- rent drain is 6 amperes . PEI = 12 X 6 = 72 watts 192. Review Problems - Dc Electricity a . ( 1 ) The resistance ...
... flows through it . PI2R = 52 X 50 = 1,250 watts Example 2 : Find the power delivered by a 12 - volt battery when the cur- rent drain is 6 amperes . PEI = 12 X 6 = 72 watts 192. Review Problems - Dc Electricity a . ( 1 ) The resistance ...
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20 ohms ac circuit ac series circuit amperes antilog applied voltage base bers binary numbers capacitive reactance Centimeters/second Change Colang Tong complex numbers Cosec Cubic meters current flowing decibels decimal number decimal point denominator digit Divide equal Example exponents factors feet Figure Find the area Find the voltage formula fraction graph hairline hypotenuse inductive reactance Kilometers leads the applied logarithm mantissa Meters/minute Meters/second Microhenrys Miles/hour Miles/minute monomial Multiply negative numbers oblique triangle ohms Ounces avoirdupois Paragraph parallel circuit percent phase angle Plot problem quadratic equation quantity R₁ radians radical radicand ratio rectangle resistor right triangle ABC scale scientific notation series circuit side opposite Simplify slide rule square root Statcoulombs Statvolts Step Subtract Tang Colang tion triangle ABC fig trigonometric functions unknown vector diagram voltage drop volts watts yards zero