...period, put its root for the firft figure of the root fought, and Subtract the number itfelf from faid left-hand period; and to the remainder annex the next period for a dividend. Find a divifor, by multiplying the fquare of the part of the root found by 300, divide the dividend...

...the right hand of the given number, as in division. Subtract the square of this root from the first period ;and to the remainder, annex the next period, for a dividend. Double the root already found, and place it to the left hand of the dividend. Consider, what figure can be annexed to thi» divisor...

...the quotient, as in Division, and place iU square under, and subtract 'A from, the above-mentioned period, and to the remainder annex the next period, for a dividend. Double the part of the root already found, and place it on the left of the dividend for a trial divisor, find...

...contained in it, if it be not a cute tUelf. (3.) Subtract the third power of this figure from the first period, and to the remainder annex the next period for a dividend, and for part of the divisor take 300 times the square of the part of the root already obtained. ^.)...

...the greatest cube in the left-hand period, put its root in the quotient, subtract the cube from that period, and to the remainder annex the next period for a dividend. Multiply the square of the root by 300 for a divisor, and take it out of the dividend, the quotient...

...which write in the quotient or root, and the square thereof under the same period ; subtract therefrom, and to the remainder annex the next period for a dividend. Double the quotient for a divisor ; see how often the divisor is contained in the dividend, with this consideration,...

...period, enter it under the period, and its root in the quotient place, tahe this 3rd power from the period, and to the remainder annex the next period for a dividend. III. Divide this dividend, omitting the last two figures, by three times the 2nd power of the figure...

...that on the left, and place its root on the right. 3. Subtract this square number from the highest period, and to the remainder annex the next period for a dividend. 4. Double the figure of the root found for a divisor ; find how often it is contained in the dividend,...

...trial the greatest cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by 3 for a TRIAL DIVISOR ; divide...

...right as the highest order of the root. 3. Subtract the square of the root figure from the left hand period, and to the remainder annex the next period for a dividend. 4. Double the part of the root already found for a trial divisor, and see how many times it is contained...