Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous Practical ProblemsIvison, Blakeman, Taylor, 1860 - 453 páginas |
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Página 248
... C to the right be marked + , those from C to the left must be marked ; and if distances from Cupwards be considered ... sine and cosine , it follows that the algebraic signs of all the circular functions result from those of the sine and ...
... C to the right be marked + , those from C to the left must be marked ; and if distances from Cupwards be considered ... sine and cosine , it follows that the algebraic signs of all the circular functions result from those of the sine and ...
Página 252
... sin . 1 = cot . = sin . A + sin.B = 2sin . ( 4 + B ) A - B ( 프 ) COS . sin.A — sin.B = 2cos . ( 4 + 13 ) sin . A + ... ( C ) , we find , ( D ) sin.Asin.B = tan . cos.A + cos.B sin . A + sin . B cos . B - cos.A sin.A - sin.B cos . A cos.B ...
... sin . 1 = cot . = sin . A + sin.B = 2sin . ( 4 + B ) A - B ( 프 ) COS . sin.A — sin.B = 2cos . ( 4 + 13 ) sin . A + ... ( C ) , we find , ( D ) sin.Asin.B = tan . cos.A + cos.B sin . A + sin . B cos . B - cos.A sin.A - sin.B cos . A cos.B ...
Página 255
... c = R : sin . C CA : AB = CE : EG or , b : c = R : tan . C CA : CB CE : CG or , b : a = R : sec . C = Hence the proposition . SCHOLIUM . If the hypotenuse of a triangle is made radius , one side is the sine of the angle opposite to it ...
... c = R : sin . C CA : AB = CE : EG or , b : c = R : tan . C CA : CB CE : CG or , b : a = R : sec . C = Hence the proposition . SCHOLIUM . If the hypotenuse of a triangle is made radius , one side is the sine of the angle opposite to it ...
Página 261
... sin . ' C = c + b - a c + b + a But . - 2 2 ab a , and c + a - b = 2 c + a + b 2 - b . a + b + c Put = 8 , as before ; then , 2 sin . C Ꮽ = a ) ( 8 ab - b ) By taking equation ( p ) , and proceeding in the same manner , we have sin . B ...
... sin . ' C = c + b - a c + b + a But . - 2 2 ab a , and c + a - b = 2 c + a + b 2 - b . a + b + c Put = 8 , as before ; then , 2 sin . C Ꮽ = a ) ( 8 ab - b ) By taking equation ( p ) , and proceeding in the same manner , we have sin . B ...
Página 263
... sin.A. versed sin . A = 2sin . ' A. 2d . From C as describe a circle . AB , and call it A ; the center , with CA as the radius , Take any arc , and AD a less arc , and call it B ; then BD is the difference of the two arcs , and must be ...
... sin.A. versed sin . A = 2sin . ' A. 2d . From C as describe a circle . AB , and call it A ; the center , with CA as the radius , Take any arc , and AD a less arc , and call it B ; then BD is the difference of the two arcs , and must be ...
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Términos y frases comunes
AB² ABCD altitude angle opposite axis bisected chord circle circumference circumscribed common cone convex surface cos.a cos.b cos.c Cosine Cotang diagonal diameter dicular difference distance divided draw equal angles equation equiangular equivalent find the angle four magnitudes frustum given line greater half Hence the theorem homologous hypotenuse included angle inscribed intersect isosceles less Let ABC logarithm measured multiplied N.sine number of sides opposite angles parallelogram parallelopipedon pendicular perpen perpendicular plane ST polyedron PROBLEM produced Prop proportion PROPOSITION prove pyramid quadrantal radii radius rectangle regular polygon right angles right-angled spherical triangle right-angled triangle SCHOLIUM secant segment similar sin.a sin.b sin.c sine solid angles sphere SPHERICAL TRIGONOMETRY straight line subtracting Tang tangent three angles three sides triangle ABC triangular prisms triedral angles TRIGONOMETRY vertex vertical angle volume
Pasajes populares
Página 320 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Página 65 - If four magnitudes are in proportion, the sum of the first and second is to their difference as the sum of the third and fourth is to their difference.
Página 121 - In a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle ; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF.
Página 56 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Página 34 - Conversely: if two angles of a triangle are equal, the sides opposite to them are equal, and the triangle it itosceles.
Página 126 - To inscribe a regular polygon of a certain number of sides in a given circle, we have only to divide the circumference into as many equal parts as the polygon has sides : for the arcs being equal, the chords AB, BC, CD, &c.
Página 22 - If two parallel lines are cut by a third straight line, the sum of the two interior angles on the same side of the secant line is equal to two right angles.
Página 277 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Página 94 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Página 30 - Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.