Explanatory mensuration for the use of schools1871 |
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Página 6
... yard . 5 yards 40 poles or 220 yards = 8 furlongs or 1,760 yds . Also 723 inches 100 links or 22 yds . 80 chains TABLES . 1 pole . = 1 fur . = 1 mile . = 1 link . = 1 chain . = 1 mile . Square Measure . 144 sq . inches 9 sq . feet 30 sq .
... yard . 5 yards 40 poles or 220 yards = 8 furlongs or 1,760 yds . Also 723 inches 100 links or 22 yds . 80 chains TABLES . 1 pole . = 1 fur . = 1 mile . = 1 link . = 1 chain . = 1 mile . Square Measure . 144 sq . inches 9 sq . feet 30 sq .
Página 11
... building a wall round a garden , in the shape of a right - angled triangle , whose hypothenuse is 97 yds . and base 72 yds . , at 13s . 6d . per yard . ( 21 ) Two persons , travelling at the rate THE SIDES OF A RIGHT - ANGLED TRIANGLE . 11.
... building a wall round a garden , in the shape of a right - angled triangle , whose hypothenuse is 97 yds . and base 72 yds . , at 13s . 6d . per yard . ( 21 ) Two persons , travelling at the rate THE SIDES OF A RIGHT - ANGLED TRIANGLE . 11.
Página 16
... yard , costs £ 16 17s . 6d . , find the length of the room . First , if we divide £ 16 17s . 6d . by 7s . 6d . , we have 45 sq . yds . , or 405 sq . ft . , as area of the floor . Then , taking the square root of 405 , we have 20 · 12 + ...
... yard , costs £ 16 17s . 6d . , find the length of the room . First , if we divide £ 16 17s . 6d . by 7s . 6d . , we have 45 sq . yds . , or 405 sq . ft . , as area of the floor . Then , taking the square root of 405 , we have 20 · 12 + ...
Página 17
... yards the side of a square field which con- tains 10 acres . ( 16 ) A square field contains 10 acres ; find the ... yard ? ( 20 * ) Determine the side of a square field which cost £ 57 158. 2 d . trenching , at 2ąd . per square yd . 7 ...
... yards the side of a square field which con- tains 10 acres . ( 16 ) A square field contains 10 acres ; find the ... yard ? ( 20 * ) Determine the side of a square field which cost £ 57 158. 2 d . trenching , at 2ąd . per square yd . 7 ...
Página 20
... yards of carpet , of a certain width , that will be required for a floor . - Find the area of the floor , and divide it by the width of the carpet . ( Observe that the area of the floor and the width of the carpet must be both expressed ...
... yards of carpet , of a certain width , that will be required for a floor . - Find the area of the floor , and divide it by the width of the carpet . ( Observe that the area of the floor and the width of the carpet must be both expressed ...
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Términos y frases comunes
ABCD Area of base Arithmetic avoirdupois axis centre chains chord of half circle circular ends circumference cone contains cube cubic feet cubic foot cubic inches curved surface cylinder depth diagonal dimensions divide edge EFGH ellipse equal Example 1.-Find Example 2.-The find its volume find the area Find the cost find the diameter find the height find the length Find the number Find the volume Formulæ frustum gonal half the arc hypothenuse Note 1.-To find oblique parallel sides parallelogram parallelopiped perimeter perpendicular distance perpendicular height poles polygon prism prismoid Prob pyramid quotient radius rectangle respectively rhombus right-angled triangle right-cone ring roods sector segment semicircle shape side faces slant height solid sphere square pyramid square root straight line thick trapezium trapezoid water weighs 1000 wedge weighs 1000 oz whole surface wide width yards zoid
Pasajes populares
Página 23 - RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area.
Página 118 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.
Página 63 - Or, from 8 times the chord of half the arc, subtract the chord of the whole arc, and $ of the remainder will be the length of the arc, nearly.
Página 33 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Página 19 - A rectangle is a four-sided figure like a square, in which the sides are perpendicular to each other, but the adjacent sides are not equal. 280. A parallelogram is a foursided figure which has its opposite sides equal and parallel, but its angles not right angles. The line DE, perpendicular to the base, is called the altitude.
Página 149 - Such a work will be of value to a candidate as a test of his ability to work the Arithmetical problems he is likely to have given him to solve in his examination ; but when it is used simply as a means of cramming the pupil, it becomes pernicious. We notice Mr. Hiley has carefully arranged...