Elementary Algebra: Second Year CourseMacmillan, 1916 |
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Página 105
... mantissa . For example , log 31.6227+ = 1.5 . The characteristic of log 31.6227+ is 1 . The mantissa of log 31.6227+ is .5 . The tables of logarithms give only the mantissa ; the LOGARITHMS 105 Fundamental Theorem.
... mantissa . For example , log 31.6227+ = 1.5 . The characteristic of log 31.6227+ is 1 . The mantissa of log 31.6227+ is .5 . The tables of logarithms give only the mantissa ; the LOGARITHMS 105 Fundamental Theorem.
Página 106
... mantissa . log 85.61 + a mantissa . log 7.030+ a mantissa . log .673-1 + a mantissa . log .045 = == - 2+ a mantissa . 3+ a mantissa . Since .0078 lies between .001 and .01 , log .0078 By inspection of these relations we obtain the rule ...
... mantissa . log 85.61 + a mantissa . log 7.030+ a mantissa . log .673-1 + a mantissa . log .045 = == - 2+ a mantissa . 3+ a mantissa . Since .0078 lies between .001 and .01 , log .0078 By inspection of these relations we obtain the rule ...
Página 107
... mantissa . Suppose the two numbers are 7896.1 and 7.8961 . We have 7896.1 = 7.8961 × 1000 . By § 111 , But Hence , log 7896.1 - log 7.8961 + log 1000 . log 1000 = 3 . log 7896.1 = log 7.8961 +3 . Since the two logarithms differ by the ...
... mantissa . Suppose the two numbers are 7896.1 and 7.8961 . We have 7896.1 = 7.8961 × 1000 . By § 111 , But Hence , log 7896.1 - log 7.8961 + log 1000 . log 1000 = 3 . log 7896.1 = log 7.8961 +3 . Since the two logarithms differ by the ...
Página 108
... mantissa is found from the tables will be explained next . FINDING LOGARITHMS 115. 1. Find the logarithm of 789 . The characteristic is 2 . The mantissa is taken from the table , p . 110. The column on the ex- treme left contains the ...
... mantissa is found from the tables will be explained next . FINDING LOGARITHMS 115. 1. Find the logarithm of 789 . The characteristic is 2 . The mantissa is taken from the table , p . 110. The column on the ex- treme left contains the ...
Página 111
... mantissa 2355. On page 109 find the mantissa 2355. It occurs in the same row as the number 17 on the extreme left , and in the column headed " 2. " The order of the figures in the answer is 172 . Where should the decimal point be ? That ...
... mantissa 2355. On page 109 find the mantissa 2355. It occurs in the same row as the number 17 on the extreme left , and in the column headed " 2. " The order of the figures in the answer is 172 . Where should the decimal point be ? That ...
Términos y frases comunes
a²b² a²x² ab² addition and subtraction algebra arithmetical arithmetical means arithmetical series ax² binomial BINOMIAL THEOREM called coefficient commutative law complete divisor completing the square Compute cube root decimal places denominator determinants diameter digits distance Divide both sides dividend division Draw a graph exponent Factor Theorem Find the h. c. f. Find the square Find the sum fixed number formula fraction geometrical series given equation Hence imaginary numbers inches linear equations logarithms mantissa negative numbers nth root number of terms obtain parenthesis polynomial positive numbers principal root quadratic equation quotient radius rational integral expression remainder Simplify solution Solve square root Substitute trial divisor triangle Type form Univ variable weight zero
Pasajes populares
Página 6 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Página 85 - In any proportion, the product of the means is equal to the product of the extremes.
Página 39 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Página 113 - The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor.
Página 65 - In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing by the number of the preceding term.
Página 5 - Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.
Página 37 - Both terms of a fraction may be divided by the same number without changing the value of the fraction.
Página 89 - Find the area of a circle whose radius is 12 feet, from the law that the area of a circle varies as the square of its radius.
Página 65 - The exponent of b in the second term is 1, and increases by 1 in each succeeding term.
Página 196 - A person engaged to work a days on these conditions : for each day he worked he was to receive b cents, and for each day he was idle he was to forfeit с cents. At the end of a days he received d cents. How many days was he idle ? 76.