Elementary Algebra: Second Year CourseMacmillan, 1916 |
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Página v
... third half year . The material is so arranged that the choice of topics for review . or advance study may be easily made . The book contains not only a large number of practical problems but also practical applications of graphs ...
... third half year . The material is so arranged that the choice of topics for review . or advance study may be easily made . The book contains not only a large number of practical problems but also practical applications of graphs ...
Página 29
... third remainder is 0 , x2 - 3x + 6 is the required square root . EXERCISES 42. Find the square root of : 1. 4 a6 28 a3b6 + 49 612 . - 2. 4 a2 12 ab + 4 ac + 9 b2 6 bc + c2 . - 3. x2 - 2xy + 6x + y2 −6 y +9 . 4. 4 x4-20 x3 - 30 x + 9 + ...
... third remainder is 0 , x2 - 3x + 6 is the required square root . EXERCISES 42. Find the square root of : 1. 4 a6 28 a3b6 + 49 612 . - 2. 4 a2 12 ab + 4 ac + 9 b2 6 bc + c2 . - 3. x2 - 2xy + 6x + y2 −6 y +9 . 4. 4 x4-20 x3 - 30 x + 9 + ...
Página 51
... third method depends upon the formula derived from the solution of the type form of the complete quadratic . Solve Transpose c , Divide by a , Add • 9 ) 23 a Take the square root , ax2 + bx + c = = 0 . ax2 + bx = - C. α b2 4 a2 - b x2 + ...
... third method depends upon the formula derived from the solution of the type form of the complete quadratic . Solve Transpose c , Divide by a , Add • 9 ) 23 a Take the square root , ax2 + bx + c = = 0 . ax2 + bx = - C. α b2 4 a2 - b x2 + ...
Página 55
... third shall have as many times the share of the second as there are dimes in the first person's share . 28. The population of a city increases from 20,000 to 20,808 in two years . What is the annual rate of increase per hundred ? 29. A ...
... third shall have as many times the share of the second as there are dimes in the first person's share . 28. The population of a city increases from 20,000 to 20,808 in two years . What is the annual rate of increase per hundred ? 29. A ...
Página 59
... third factor can be found by dividing x6 + 2 x5 . uct of x - 1 and x + 2 ; that is , by x2 + x- - 2 . x2 + x3 + x2 + x + 1 . Hence we have , - х - - 2 = 0 , hence 2 by the prod- The quotient is · ( x − 1 ) ( x + 2 ) ( x2 + x3 + x2 + x ...
... third factor can be found by dividing x6 + 2 x5 . uct of x - 1 and x + 2 ; that is , by x2 + x- - 2 . x2 + x3 + x2 + x + 1 . Hence we have , - х - - 2 = 0 , hence 2 by the prod- The quotient is · ( x − 1 ) ( x + 2 ) ( x2 + x3 + x2 + x ...
Términos y frases comunes
a²b² a²x² ab² addition and subtraction algebra arithmetical arithmetical means arithmetical series ax² binomial BINOMIAL THEOREM called coefficient commutative law complete divisor completing the square Compute cube root decimal places denominator determinants diameter digits distance Divide both sides dividend division Draw a graph exponent Factor Theorem Find the h. c. f. Find the square Find the sum fixed number formula fraction geometrical series given equation Hence imaginary numbers inches linear equations logarithms mantissa negative numbers nth root number of terms obtain parenthesis polynomial positive numbers principal root quadratic equation quotient radius rational integral expression remainder Simplify solution Solve square root Substitute trial divisor triangle Type form Univ variable weight zero
Pasajes populares
Página 6 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Página 85 - In any proportion, the product of the means is equal to the product of the extremes.
Página 39 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Página 113 - The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor.
Página 65 - In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing by the number of the preceding term.
Página 5 - Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.
Página 37 - Both terms of a fraction may be divided by the same number without changing the value of the fraction.
Página 89 - Find the area of a circle whose radius is 12 feet, from the law that the area of a circle varies as the square of its radius.
Página 65 - The exponent of b in the second term is 1, and increases by 1 in each succeeding term.
Página 196 - A person engaged to work a days on these conditions : for each day he worked he was to receive b cents, and for each day he was idle he was to forfeit с cents. At the end of a days he received d cents. How many days was he idle ? 76.