Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of Practical Arithmetic: Adapted to the Use of Schools in the United States ...W.&J.Bolles, 1839 |
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Página 16
... Hence it appears that any figure in the unit's place , expresses its simple value only , or so many ones ; but in the second place , or place of tens , it becomes so many tens , or ten times its simple value ; and in the third place ...
... Hence it appears that any figure in the unit's place , expresses its simple value only , or so many ones ; but in the second place , or place of tens , it becomes so many tens , or ten times its simple value ; and in the third place ...
Página 24
... Hence it follows that any sum in federal money may be performed as in whole numbers . The dollar is the money unit ; and to distinguish dollars from the smaller denominations , & point , or comma ( , ) cal- led a separatrix , is placed ...
... Hence it follows that any sum in federal money may be performed as in whole numbers . The dollar is the money unit ; and to distinguish dollars from the smaller denominations , & point , or comma ( , ) cal- led a separatrix , is placed ...
Página 29
... Hence is derived the Rule . " When the lower figure is greater than the figure above it add 10 to the upper figure , " & c . Proof . The remainder and less number added together are equal to the greater number , therefore the work is ...
... Hence is derived the Rule . " When the lower figure is greater than the figure above it add 10 to the upper figure , " & c . Proof . The remainder and less number added together are equal to the greater number , therefore the work is ...
Página 34
... Hence we find that 3 times 365 is equal to 1095. We might have obtained this same answer by setting down 365 the multiplicand 3 times and adding it up . 2 3 4 5 6 5432 2345 9054 152634 2 3 4 5 6 Multiplicand 57436 Multiplier Product ...
... Hence we find that 3 times 365 is equal to 1095. We might have obtained this same answer by setting down 365 the multiplicand 3 times and adding it up . 2 3 4 5 6 5432 2345 9054 152634 2 3 4 5 6 Multiplicand 57436 Multiplier Product ...
Página 37
... Hence the following RULE . Place the ciphers of the multiplier on the right of the multiplicand and it makes the product required . EXAMPLES . by 10 , the product is 560 by 100 1. Multiply 56 2. Multiply 548 3. Multiply 85 4. Multiply ...
... Hence the following RULE . Place the ciphers of the multiplier on the right of the multiplicand and it makes the product required . EXAMPLES . by 10 , the product is 560 by 100 1. Multiply 56 2. Multiply 548 3. Multiply 85 4. Multiply ...
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Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of ... Nathan Daboll Sin vista previa disponible - 2016 |
Términos y frases comunes
2qrs 3qrs acres 3 roods annex annuity answer Arithmetic barrels bought broadcloth bushels called cent per annum ciphers circumference common denominator common difference Compound Interest contained cords cost cube root currency diameter dividend dollars dols equal EXAMPLES farthings Federal money find the amount find the present Find the sum Find the value foot frustrum gain or loss gallons given number given sum greatest common divisor hogshead hundred improper fraction last term leave length lowest terms merchant miles mills mixed number months multiplicand Multiply Note number of terms paid payment pence pint pound present worth principal PROB proportion quantity quarts Questions quotient rate per cent ratio Reduce remainder right hand Rule of Three separatrix shillings sold solid contents square rods square root subtract subtrahend tens third term thousand units VULGAR FRACTIONS weight whole number yards of cloth
Pasajes populares
Página 205 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Página 189 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Página 193 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Página 122 - A and B depart from the same, place and travel the same road ; but A goes 5 days before B, at the rate of 15 miles a day . B follows at the rate of 20 miles a . day } what distance must he travel to overtake A ? Ans. 300 miles RULE OF THREE INVERSE.
Página 181 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Página 88 - To reduce an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Página 124 - ... multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term.
Página 231 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Página 173 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Página 178 - If a footman travel 130 miles in 3 days, when the days are 12 hours long ; in how many days, of 10 hours each, may he travel 360 miles ? Ans. 9|f days. 5. If 120 bushels of corn can serve 14 horses 56 days, how many days will 94 bushels serve 6 horses?