 | William James Milne - 1877 - 402 páginas
...every triangle is one-half of a parallelogram of the same base and altitude. Therefore, RULE. — The area of a triangle is equal to one-half the product of the base by the altitude. When the three sides are given, the following is the rule: RULE. — From half... | |
 | George Albert Wentworth - 1882 - 234 páginas
...5° 44' 23" B =11° 29' A =78° 31' TRIGONOMETRY. § 16. AREA OF THE EIGHT TRIANGLE. It is shown in Geometry that the area of a triangle is equal to one-half the product of the base by the altitude. Therefore, if a and b denote the legs of a right triangle, and jFthe area, ,-,... | |
 | George Albert Wentworth - 1884 - 330 páginas
...- 9.00218 \B -5° 44' 21" B =11° 29' A =7S°31' § 16. AREA OF THE RIGHT TRIANGLE. It is shown in Geometry that the area of a triangle is equal to one-half the product of the base by the altitude. Therefore, if a and b denote the legs of a right triangle, and .Fthe area, ,-,_... | |
 | George Albert Wentworth - 1887 - 206 páginas
...=5° 44' 21" B =11° 29' A =78° 31' TRIGONOMETRY. § 16. ABEA OF THE RIGHT TRIANGLE. It is shown in Geometry that the area of a triangle is equal to one-half the product of the base by the altitude. Therefore, if a and b denote the legs of a right triangle, and F the area, F=lab.... | |
 | George Albert Wentworth - 1887 - 346 páginas
...log tan IB =9.0021.8 B =5° 44' 21" B TRIGONOMETRY. § 16. AREA OF THE RIGHT TRIANGLE. It is shown in Geometry that the area of a triangle is equal to one-half the product of the base by the altitude. Therefore, if a and b denote the legs of a right triangle, and area, By means... | |
 | George Albert Wentworth - 1887 - 264 páginas
...triangle whose vertices are the points (2, 1), (3, - 2), (- 4, - 1). A ns. 10. It is shown in Elementary Geometry that the area of a triangle is equal to one-half the product of its base and its altitude ; hence this problem may be solved by performing the following operations... | |
 | New Jersey. State Board of Education - 1888 - 694 páginas
...equal." 3. Prove that the sum of the angles of any triangle is equal to two right angles. 4. Prove that the area of a triangle is equal to one-half the product of its base and altitude. 5. Prove that the side of a regular inscribed hexagon is equal to the radius... | |
 | Michigan. Department of Public Instruction - 1892 - 524 páginas
...altitude of the triangle, and its area. 7. What is a circle? A radius? An equilateral polygon? 8. Prove that the area of a triangle is equal to one-half the product of the base and altitude. ARITHMETIC. [First and Second Gtadee.] 1. Make and solve a problem illustrating... | |
 | William Shaffer Hall - 1893 - 88 páginas
...number of linear units in one line by the number of units of the same kind in the other line. Thus, the area of a triangle is equal to one-half the product of the number of linear units in the base, by the number of linear units in the altitude. The expression,... | |
 | George Albert Wentworth, George Anthony Hill - 1894 - 150 páginas
...given the base, the vertical angle, and the length of the bisector of the vertical angle. 3. Prove that the area of a triangle is equal to onehalf the product of its perimeter by the radius of the inscribed circle. 77. Propositions 136, 237, 261. 1. Prove that... | |
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The area of a triangle is equal to one-half the product of the base by the altitude ; therefore, if a and b denote the legs of a right triangle, and F the area, F = \ ab. 
