 | John Radford Young - 1833 - 308 páginas
...side, by Napier's analogies, seems somewhat lengthy. But a shorter method of solution is deducible from the fundamental formula, cos. с = cos. a cos. b + sin. a sin. 6 соя. С .... (1). For substituting cos. a tan. a for its equal sin. a it becomes cos. с = cos.... | |
 | Christoph Gudermann - 1835 - 406 páginas
...alfo cos A + cos B cos С = sin B sin G cos a, ebenfo cos B + cos A cos G = sin A sin G cos Ь tinb cos С + cos A cos B = sin A sin B cos c, alfo sin A2 sin a1 + sin B2 sin/?2 -f sin C5 sin y2 -J- 2 sin A sin B cos с sin a sin ß + 2 sin A... | |
 | John Charles Snowball - 1837 - 322 páginas
...sin В . sin C 30. То shew that Sin с . cos A = cos a . sin b — sin a . cos b . cos C. By (ii), cos с = cos a . cos b + sin a . sin b . cos C. So also, sin b . sin с . cos A = cos a — cos 6 . cos с — cos a — cos6 . (cos a . cos b + sin... | |
 | Louis Puissant - 1842 - 568 páginas
...aux angles de mêmes dénominations ; on aura cos a = cos b cos с •+- sin b sin с cos A , ( i ) cos с = cos a cos b •+- sin a sin b cos C, (2) sin A sin с = sin a sin C. (3) Si l'on différencie les deux premières équations, en faisant... | |
 | Charles Hutton - 1843 - 570 páginas
...generally considered preferable. Second method : to find с by means of a subsidiary angle. By (4), cos с = cos a cos b + sin a sin b cos C, = cos a (cos b + tan a sin b cos C) / COS ш\ „ Assume cot ш I = - I = tan a cos С ; \ sin ы/... | |
 | Lefébure de Fourcy (M., Louis Etienne) - 1848 - 582 páginas
...cos a = cos b cos с -(- sin b sin с cos A, [2] cos b = cos a cos с -\- sin a sin с cos B , [3] cos с = cos a cos b -\- sin a sin b cos C. 97. 2) (Relation $п^феп ¿hm (Seiten unb iCrtn jiuei ©egenwinteln. lim biefe, ber (Kombination... | |
 | Delisle - 1851 - 226 páginas
...= — cos' B cos C -f- sin B sin G cos a , (i3) cos B = — cos A cos С + sin A sin С cos b, (Ц) cos С = — cos A cos B -+- sin A sin B cos c, au moyen desquelles on pourra déterminer les côtés d'un triangle, lorsque les angles seront donnés.... | |
 | Carl Bremiker - 1852 - 632 páginas
...utuntur. Est enim haec: sin В sin с = sin b sin C cos В sin с t= cos b sin a — sin b cos a cos С cos с = cos a cos b + sin a sin b cos C. Quae aequationee etiam sic scribi possunt, ut A pro ti ponas, dummodo b in a mutaveris. Eaedem aequationes... | |
 | Carl Bremiker - 1852 - 618 páginas
...utuntur. Est cnirn haec: sin В sin с = sin b sin С cos В sin с es cos b sin a — sin b cos a cos С cos с = cos a cos b + sin a sin b cos C. Quae aequationes etiam sic scribi possunt, ut A pro В ponas, dummodo b in a mutaveris. Eaedem aequationes... | |
 | Royal Military Academy, Woolwich - 1853 - 476 páginas
...cos с cos b -\- sin с sin b cos A . . . (1). cos 6 = cos a cos с + sino sin с cos B . . . (2), cos с = cos a cos b + sin a sin b cos C . . . (3). These are the most important formulœ of Spherical Trigonometry. They are transformed to... | |
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... cos a = cos b cos с + sin b sin с cos A ; (2) cos b = cos a cos с + sin a sin с cos в ; ^ A. (3) cos с = cos a cos b + sin a sin b cos C. 
