The Elements of Euclid, Libros 1-6;Libro 11 |
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Página 63
But it has been shewn that the square on AE is also double of the square on AC . Therefore the squares on AE , EF are double of tho squares on AC , CD . But the square on AF is equal to the squares on E , EF , because the angle AEF is a ...
But it has been shewn that the square on AE is also double of the square on AC . Therefore the squares on AE , EF are double of tho squares on AC , CD . But the square on AF is equal to the squares on E , EF , because the angle AEF is a ...
Página 65
And because EC is equal to CA , the square on EC is oqual to the square on CA ; therefore the squares on EC , CA are double of the square or CA. But the squareon AE is equal to the squares on EC , CA . [ I . 47 .
And because EC is equal to CA , the square on EC is oqual to the square on CA ; therefore the squares on EC , CA are double of the square or CA. But the squareon AE is equal to the squares on EC , CA . [ I . 47 .
Página 127
Therefore the angle BFC is double of the angle CFR , and the angle BẮC is double of the angle CKF . For the same reason the angle CFD is double of the angle CFL , and the angle OLD is double of the angle CLF .
Therefore the angle BFC is double of the angle CFR , and the angle BẮC is double of the angle CKF . For the same reason the angle CFD is double of the angle CFL , and the angle OLD is double of the angle CLF .
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ABCD angle ABC angle ACB angle BAC Axiom base BC is equal bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson solid square straight line &c suppose Take taken THEOREM third touches the circle triangle ABC Wherefore whole