The Elements of Euclid, Libros 1-6;Libro 11J.M. Dent & Sons, Limited, 1933 - 298 páginas |
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Página 42
... join EC . [ I. 31 . B Then the triangle ABC is equal to the triangle EBC , because they are on the same base BC ... Join AD . AD shall be parallel to BF . For if it is not , through A draw AG parallel to BF , meeting ED at G and join GF ...
... join EC . [ I. 31 . B Then the triangle ABC is equal to the triangle EBC , because they are on the same base BC ... Join AD . AD shall be parallel to BF . For if it is not , through A draw AG parallel to BF , meeting ED at G and join GF ...
Página 84
... joins the points F , G , shall pass through the point 4 . For , if not , let it pass otherwise , if pos- sible , as FCDG , and join FA , AG . Then , because Fis the centre of the cir- cle ABC , FA is equal B to FC ; [ I. Def . 15 . and ...
... joins the points F , G , shall pass through the point 4 . For , if not , let it pass otherwise , if pos- sible , as FCDG , and join FA , AG . Then , because Fis the centre of the cir- cle ABC , FA is equal B to FC ; [ I. Def . 15 . and ...
Página 266
... join and form one straight line . Take GH and EK each equal to AB , and join HC , CK , KF , FH . D K A H B Then it may be shewn that the triangle HBC is equal in F all respects to the triangle FEK , and the triangle KDC to the triangle ...
... join and form one straight line . Take GH and EK each equal to AB , and join HC , CK , KF , FH . D K A H B Then it may be shewn that the triangle HBC is equal in F all respects to the triangle FEK , and the triangle KDC to the triangle ...
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Términos y frases comunes
ABCD AC is equal adjacent angles angle ABC angle ACB angle BAC angle DEF angle EDF angles equal Axiom base BC bisected centre circle ABC circumference Constr Construction Corollary Definition 15 demonstration diameter double draw equal angles equal to F equiangular equimultiples Euclid Euclid's Elements exterior angle fourth given circle given straight line gnomon greater ratio greater than F Hypothesis less Let ABC Let the straight meet multiple opposite angle parallel to BC parallelogram perpendicular polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION rectangle contained remaining angle right angles segment shewn sides similar and similarly Simson square described square on AC straight line &c straight line AB THEOREM tiples touches the circle triangle ABC triangle DEF twice the rectangle Wherefore