The Elements of Euclid, Libros 1-6;Libro 11 |
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Página 93
For the same reason the angle FEC is double of the anglo EAC . Therefore the whole angle BEC is double of the whole angle BAC Next , Ict the centre of the circlo bo without the angle BAC Then it may be shewn , as inthe first casc ...
For the same reason the angle FEC is double of the anglo EAC . Therefore the whole angle BEC is double of the whole angle BAC Next , Ict the centre of the circlo bo without the angle BAC Then it may be shewn , as inthe first casc ...
Página 126
For the same reason the angles at the points B , D are right angles . And because the angle FCK is a right angle ... For the same reason the square on FK is equal to the squares on FB , BK . Therefore the squares on FC , CK are equal to ...
For the same reason the angles at the points B , D are right angles . And because the angle FCK is a right angle ... For the same reason the square on FK is equal to the squares on FB , BK . Therefore the squares on FC , CK are equal to ...
Página 201
For the same reason the triangle EBC is to the triangle LGH in the duplicate ratio of EB to LG . Therefore the triangle ABE is to the triangle FGL as the triangle EBC is to the triangle LGH . [ V. 11 Again , because the triangle EBC is ...
For the same reason the triangle EBC is to the triangle LGH in the duplicate ratio of EB to LG . Therefore the triangle ABE is to the triangle FGL as the triangle EBC is to the triangle LGH . [ V. 11 Again , because the triangle EBC is ...
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Términos y frases comunes
ABCD angle ABC angle ACB angle BAC Axiom base BC is equal bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson solid square straight line &c suppose Take taken THEOREM third touches the circle triangle ABC Wherefore whole
Información bibliográfica
| Título | The Elements of Euclid, Libros 1-6;Libro 11 Tema 891 de Everyman's library Tema 891 de Everyman's library, ed. by Ernest Rhys. Science. [No. 891] Tema 891 de Everyman's library: Science |
| Autor | Euclid |
| Editores | Isaac Todhunter, Robert Simson |
| Editor | J.M. Dent & Sons, Limited, 1933 |
| Procedencia del original | Universidad de California, Berkeley |
| Digitalizado | 5 Ago. 2019 |
| Largo | 298 páginas |
| Exportar cita | BiBTeX EndNote RefMan |