College AlgebraScott, Foresman, 1901 - 777 páginas |
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Página vi
... problem of Algebra is the solution of the equation , and with the irrational and complex numbers the system of ... problems in maximum and minimum values of fractions which can be solved by means of quadratic equations . Following the ...
... problem of Algebra is the solution of the equation , and with the irrational and complex numbers the system of ... problems in maximum and minimum values of fractions which can be solved by means of quadratic equations . Following the ...
Página xii
... PROBLEMS INVOLVING LITERAL EQUATIONS Formulae and Rules Problems Solved for Illustration CHAPTER V INTERPRETATION OF THE SOLUTION OF PROBLEMS Positive and Negative Solutions Zero Solutions Indeterminate Solutions Infinite Solutions ...
... PROBLEMS INVOLVING LITERAL EQUATIONS Formulae and Rules Problems Solved for Illustration CHAPTER V INTERPRETATION OF THE SOLUTION OF PROBLEMS Positive and Negative Solutions Zero Solutions Indeterminate Solutions Infinite Solutions ...
Página xv
... Problems Problems connected with the Theorem of Pythagoras Problems concerning the Areas of Plane Figures 409 412 418 CHAPTER VI RELATIONS BETWEEN the CoefficienTS AND ROOTS OF A QUADRATIC EQUATION An Equation of the Second Degree has ...
... Problems Problems connected with the Theorem of Pythagoras Problems concerning the Areas of Plane Figures 409 412 418 CHAPTER VI RELATIONS BETWEEN the CoefficienTS AND ROOTS OF A QUADRATIC EQUATION An Equation of the Second Degree has ...
Página xviii
... Problem of the Number of Arrangements of n Things taken r at a time and n at a time Permutations Circular Permutation Combinations and Special Theorems Problems CHAPTER III FORMULA FOR THE EXPANSION OF A BINOMIAL 591 592 593 595 598 599 ...
... Problem of the Number of Arrangements of n Things taken r at a time and n at a time Permutations Circular Permutation Combinations and Special Theorems Problems CHAPTER III FORMULA FOR THE EXPANSION OF A BINOMIAL 591 592 593 595 598 599 ...
Página 28
... problem above would . + be indicated algebraically as follows : + $ 250.50 . $ 321.50 + $ 250.50 = $ 0.00 - $ 71.00 $ 71.00 . - - - $ 250.50 $ 71.00 That is , there remains a debt of $ 71.00 , or the balance is a negative number . 21 ...
... problem above would . + be indicated algebraically as follows : + $ 250.50 . $ 321.50 + $ 250.50 = $ 0.00 - $ 71.00 $ 71.00 . - - - $ 250.50 $ 71.00 That is , there remains a debt of $ 71.00 , or the balance is a negative number . 21 ...
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Términos y frases comunes
A₁ algebraic Arithmetic ax² b₁ binomial Binomial Theorem c₁ CHAPTER coefficients common convergent corresponding cube root decimal definition denominator determinant difference divided division divisor equal equivalent example exponent expression factors figures Find the number formula fraction given equation greater Hence imaginary increases inequality integer irrational less limit log 1+r logarithm mantissa mathematical induction monomial multiplied negative number nth root number of terms P₁ partial fractions polynomial positive integer positive number problem quadratic quadratic equation quotient rational remainder result rule satisfy second degree second member solution Solve the equations square root substituting subtraction Suppose surd symbols system of equations theorem third tion triangle trinomial unknown numbers unknown quantities Va² zero
Pasajes populares
Página 205 - Nos. 1 and 2, 3 and 4, 5 and 6, 7 and 8, 9 and 10, 11 and 12.
Página 666 - Q(x) to obtain a quotient (polynomial of the form -Q ) plus a rational function (remainder divided by the divisor) in which the degree of the numerator is less than the degree of the denominator.
Página 79 - Raise the absolute value of the numerical coefficient to the required power, and multiply the exponent of each letter by the exponent of the required power.
Página 71 - The part of the equation which is on the left of the sign of equality is called the first member ; the part on the right of the sign of equality, the second member.
Página 588 - What will $ 100 amount to in 7 years with interest at 8% per annum, compounded semi-annually ? 3. In how many years will a sum of money double itself at 6%, compounded annually ? 4.
Página 181 - A person has a hours at his disposal. How far may he ride in a coach which travels b miles an hour, so as to return home in time, walking back at the rate of с miles an hour ? 43.
Página 519 - In any proportion, the terms are in proportion by Alternation; that is, the first term is to the third as the second term is to the fourth.
Página 520 - In a series of equal ratios, any antecedent is to its consequent, as the sum of all the antecedents is to the sum of all the consequents. Let a: 6 = c: d = e :/. Then, by Art.
Página 524 - The first of four magnitudes is said to have the same ratio to the second, that the third has to the fourth, when any equimultiples...
Página 588 - June, 1889.) 1. In how many years will a sum of money double itself at 4 per cent., interest being compounded semi-annually ? 2.