A first book of algebra, including the binomial theorem1867 |
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Página 52
... sides of it , without altering its character as an equation , so long as the number we add or subtract is the same for both sides . Similarly , we may multiply or divide both sides of the equation by any 52 ALGEBRA .
... sides of it , without altering its character as an equation , so long as the number we add or subtract is the same for both sides . Similarly , we may multiply or divide both sides of the equation by any 52 ALGEBRA .
Página 53
... sides of an equation , we subtract the odd 19 , and .. D - : 95 and dividing by 5 : ... x = 19 . If 7x - 14 = 105 , we have the equation 7x 14 77 and adding 14 to each side : .. 7x 91 - and dividing by 7 : .. 13 . x = It will happen ...
... sides of an equation , we subtract the odd 19 , and .. D - : 95 and dividing by 5 : ... x = 19 . If 7x - 14 = 105 , we have the equation 7x 14 77 and adding 14 to each side : .. 7x 91 - and dividing by 7 : .. 13 . x = It will happen ...
Página 54
... side , and all the known numbers on the other . If we take the 4x from the right hand member there will be only 3 left , and this we may do if we take away the same quantity from the left hand member also . This will give us : 5х 4x 1 ...
... side , and all the known numbers on the other . If we take the 4x from the right hand member there will be only 3 left , and this we may do if we take away the same quantity from the left hand member also . This will give us : 5х 4x 1 ...
Página 55
... Total Here the equation is not so simple . The total amount is £ 45 more than 3x . The equation now is : 3x + 45 .. 3x = .. 102 , and subtract 45 from each side 57 = 19 . Therefore A's money = x = £ 19 B's = 57 EQUATIONS . 55.
... Total Here the equation is not so simple . The total amount is £ 45 more than 3x . The equation now is : 3x + 45 .. 3x = .. 102 , and subtract 45 from each side 57 = 19 . Therefore A's money = x = £ 19 B's = 57 EQUATIONS . 55.
Página 56
... side . .. 3x - 45 + 45 : = .. 3x = 147 . .. x = 147 102 + 45 . 49 . = 3 Therefore C's money = x B's 1 = £ 49 = X - 15 £ 34 A's = x 30 - £ 19 " " £ 102 It will be seen from this that may be used to express any unknown quantity , and that ...
... side . .. 3x - 45 + 45 : = .. 3x = 147 . .. x = 147 102 + 45 . 49 . = 3 Therefore C's money = x B's 1 = £ 49 = X - 15 £ 34 A's = x 30 - £ 19 " " £ 102 It will be seen from this that may be used to express any unknown quantity , and that ...
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A First Book of Algebra, Including the Binomial Theorem William Rossiter Sin vista previa disponible - 2016 |
Términos y frases comunes
3rd power 4th power a+b+c acres added addition algebraic fractions algebraic quantities answer arithmetic arranged B's money binomial theorem bought Clearing of fractions common difference common measures common multiples common ratio complete quotient cows cube root denominator divided division divisor equal exponent extraction figures Find the common Find the cube Find the expression Find the square find the value following examples formula gallons give given improper fraction INVOLUTION known last term less means merator miles multiplied number of days number of terms number of things numerical coefficients OXFORD STREET problem proper fraction quadratic equations quotient remainder sheep side solving square root subtraction taken tion total number Transposing unknown quantity walked whole number writing written x²+2xy x²y² yards
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Página 160 - A square court yard has a rectangular gravel walk round it. The side of the court wants 2 yards of being 6 times the breadth of the gravel walk ; and the number of square yards in the walk exceeds the number of yards in the periphery of the court by 164. Required the area of the court ? All equations of the second degree may be reduced to one of the following forms.
Página 39 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Página 169 - How many hours a day must 42 boys work, to do in 45 days what 27 men can do in 28 days of 10 hours each, the work of a boy being half that of a man ? 11. If 8 guineas be expended in purchasing Brussels carpet f yd. wide, at 3».
Página 120 - Divide the first term of the remainder by twice the first term of the root, and add the quotient to the part of the root already found, and also to the trial-divisor.
Página 120 - The square of the sum of two numbers is equal to the square of the first number plus twice the product of the first and second number plus the square of the second number.
Página 128 - N, and divide the first term of the remainder by 3 times the square of the first term of R, the quotient will be the third term of the root.
Página 206 - Eequired the numbers. 6. The sum of three numbers in geometrical progression is 35, and the mean term is to the difference of the extremes as 2 to 3. Required the numbers. Ans. 5, 10, 20. 7. The sum of £ 14 was divided between three persons, whose shares were in geometrical progression ; the sum of the shares of the first and second was to the sum of the shares of the second and third as 1 to 2.
Página 88 - Divide the number 36 into 3 such parts, that* \ of the first, \ of the second, and \ of the third, shall be equal to each other.
Página 207 - Bought two flocks of sheep for 65/. 13s., one containing 5 more than the other. Each sheep cost as many shillings as there were sheep in the flock. Required the number in each flock. Ans. 23, and 28.
Página 93 - ... 2. A can do a piece of work in a days and B in b days.