| Denison Olmsted - 1839 - 276 páginas
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into **the sine of the middle part, equals the product of the tangents of the adjacent** extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the... | |
| Denison Olmsted - 1839 - 276 páginas
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into **the sine of the middle part, equals the product of the tangents of the** sdjaeent extremes, or of the cosines of the opposite extremes. (The corresponding vowels arc marked... | |
| Denison Olmsted - 1839 - 276 páginas
...the middle part, the opposite parts are a and B. Napier's rule is as follow* : Radius into the fine **of the middle part, equals the product of the tangents of the adjacent** extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the... | |
| Anthony Dumond Stanley - 1848 - 122 páginas
...next to this and separated by it are called the adjacent parts, and the other two the opposite parts. **The SINE of the MIDDLE part, equals the product of the TANGENTS of the ADJACENT parts,** and equals the product of the COSINES of the OPPOSITE parts. This proposition may be more easily remembered,... | |
| William Chauvenet - 1852
...sides including it are regarded as adjacent. The rules are : I. The sine of the middle part is equal to **the product of the tangents of the adjacent parts. II. The sine of the middle part** is equal to the product of the cosines of the opposite parts. The correctness of these rules will be... | |
| William Somerville Orr - 1854
...then it will be found that all the formulas of the last article are included in the following rule. " **The sine of the middle part equals the product of the tangents of the adjacent parts,** and also equals the product of the cosines of the opposite parts ; " Or, Sin. mid. = tan. ad. = cos.... | |
| GEORGE R. PERKINS - 1856
...five parts is chosen as the middle part. NAPIER'S RULES, I. The sine of the middle part is equal to **the product of the tangents of the adjacent parts. II. The sine of the middle part** is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five... | |
| George Roberts Perkins - 1860 - 443 páginas
...chosen as the middle part. 90°-B 90° -T NAPIER'S RULES. I. The sine of the middle part is equal to **the product of the tangents of the adjacent parts. II. The sine of the middle part** is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five... | |
| John Daniel Runkle - 1860
...spherical triangle being placed on the circumference of a circle, NAPIER'S Bules are as follows : — RULE **I. The sine of the middle part equals the product of the** cosines of the opposite parts, RULE II. The sine of the middle part is equal to the product of the... | |
| Benjamin Greenleaf - 1861 - 490 páginas
...whatever be the middle part, we have as THE RULES OF NAPIER. I. The sine of the middle part is equal to **the product of the tangents of the adjacent parts. II. The sine of the middle part** is equal to the product of tJie cosines of the opposite parts. 168. Napier's rules may be proved by... | |
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