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Plotting these points, we have two curves, one in the first quadrant and one in the third quadrant. These two are referred to as one curve having two branches.

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Example 3. Trace the curve 2+2y216.

If x = 0, y =±√8; if y = 0, x = ±4. In the equation x2 + 2 y2 = 16, the value of x does not exceed 4, and the value of y does not exceed +√8.

For x=0, 1, ±2, ±3, ±3.5, ±√14, ±4, we find,

y = =±√8, ±√7.5, ±√6, ±√3.5, ±√1.87, ±1, 0.

In plotting these points it will be sufficient to get the values of ±√8, ±√7.5, ±√6, etc., correct to two decimal figures.

Example 4. Trace the curve x2+ y2 = 12.

For x=0, 11, 12, ±2.5, ±3, ±√12,

we find,

y=±√12, ±√11, ±√8, ±√5.75, ±√3, 0.

Plotting the points, we get a circle whose radius is ±√12.

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we find by subtracting (1) from (2), member by member,

y2 = 4,
y= ±2.

Substituting in either equation ±2 for y, we get

x=±√8.

These values of x and y are the coördinates of the four points of intersection of the two curves. This is as it should be, for the coördinates of every point on a curve satisfy the equation of the curve, and consequently if two curves have points in common, the coördinates of these points must satisfy both equations of the curves.

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4. y=(x-2)2, y = (x-3)2, y=(x+3)2.

5. x2+ y2 = 25, x2+ y2 = 16.

6. x2— y2=7, x2 — y2 = 12, x2 — y2 = 1.

7. y2=8x, y2 = 16x, y2 = 4x.

8. 2x2+3y2 = 32, 4 x2 + 9 y2 = 36.

9. y=x(6−x), y=x(4−x), y=x(1−x).

HINT. In the last one take x = .2, .5, ±.7, ±1, ±2, etc.

10. Solve x2-x+1=0. Trace the graph, y=x2−x+1. How is it situated with respect to the x-axis?

11. The number of feet a body falls under the influence of gravity in t seconds is given by the formula S = 16 ť2, where S denotes the number of feet. Trace the graph of S= 16 t2.

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From equation (2), we find, y = 5 — x.

Substitute this value of y in equation (1), and we have,

x2 + 2 (5 − x)2 = 17.

(3)

Solving equation (3), we find, x = 3 or 11.

Substituting this value of x in equation (2), y = 2, or .

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Systems of equations in two variables where one equation is quadratic and the other linear may be all solved like equation (1) above.

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11. x + y = 30, 1 1

z x − z y = 1}.

12. (3x + y) = 61,

(4x+3y) = 14}.

13. 5 x 3

4x +

y + 2 z =

30,

2y 3 z = 10,

3x + y-4 z = 0.

14. 2x7y+ 4 z = 16, 3x-2y+3 z = 32,

x + y + 5 z = 26.

15. 3x2 z = 32,
4y- z=2,
2x-3y=14.

16. 4x + 3y = 0,
z - y = 13,
7 x − 3 z = 1.

14.

17. 4 y 5x = 3,

10. 13 x 17 y = 21,

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4z-7y = 111,

3z7x=13.

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