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apparent applied beam bear becomes boiler bottom breadth breaking weight calculated cast iron cent centre compressive constant correct crushing strain cylinder dead load deflection depth dimensions direction effect Elasticity ends Engineers equal error example experimental experiments extension Factor fail falling feet long flange flat flexure foot gave girder given gives greater half hence illustrated inch diameter inch square increased joints kinds laws length less load material maximum mean metal namely nearly observed obtain ordinary pillar pitch plate practice pressure proportional ratio rectangular reduced require resistance respectively rivet-holes rivets rope rule safe shearing shown shows side similar simply sizes solid square inch steam steel strain supports Table taken tensile strain tensile strength thickness tons per square tube ultimate whole wrinkling wrought iron
Página 247 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Página 110 - ... of what would be required to crush the material, one half only of the strength may be considered as available for resistance to flexure, whilst the other half is employed to resist crushing ; and when, through the shortness of the pillar, the breaking weight is so great as to be nearly equal to the crushing force, we may consider that no part of the strength of the pillar is applied to resist flexure.
Página 214 - B from the edge of that part of the section which is subjected to tension, or from the bottom in the case of a beam supported at both ends and loaded in the usual way. This, it will be observed, is just the reverse of the mode of calculating Cast-iron beams (341).
Página 220 - ... a beam supported at both ends and loaded in the centre. The top and bottom flanges in Fig.
Página 344 - ... and tensile strains combined, so that we cannot determine the value of either alone. It will, therefore, be well to see how far this method agrees with direct experiments on such materials as cast and wrought iron, whose strength and elasticity are known with certainty (600). (638.) We require 1st from a known weight in the centre of a rectangular beam of given dimensions, to find the maximum longitudinal strains, or those at the upper and lower edges of the section. Obviously the strain varies...
Página 350 - We have here taken the load as constant, at whatever point in the length it might be placed, but the safe load increases as it moves from the centre toward the end in inverse ratio of the product of the two parts into which the length is divided by the weight (420), for example with a beam 20 feet long, a weight in the centre divides it into two lengths, each 10 feet, and we have 10 x 10 = 100 : now say Distance of Weight from Centre.
Página 81 - CHAR 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 "@ "A "B "C "D...
Página 218 - In this case the shearing stresses are the same as in a beam supported at both ends and loaded in the centre (see Appendix VIII.) Deflection.
Página 398 - No. 3, and a mixture of iron, composed of Leeswood No. 3 and Glengarnock No. 3, in equal proportions. There were two experiments upon each of the simple irons, and three upon the mixture, and the mean results were afterwards reduced to those of 10 feet and 1 square inch exactly.