 | James Ryan, Robert Adrain - 1824 - 542 páginas
...bring down the next three figures ; divide the number thus brought down by 300 times the square of the first figure of the root, and it will give the...the result from the dividend, and then bring down the next period, and so proceed till all the periods are brought down. The rules for extracting the... | |
 | James Ryan - 1824 - 550 páginas
...bring down the next three figures ; divide the number thus brought down by 300 times the square of the first figure of the root, and it will give the...the result from the dividend, and then bring down the next period, and so proceed till all the periods are brought down. The rules for extracting the... | |
 | Robert Gibson - 1832 - 290 páginas
...bring down the next three figures ; divide the number thus brought down by 300 times the square of the first figure of the root, and it will give the...of the second figure together, for a divisor ; then turned, this remainder must be twice the product of 30, and the part of the root still to be found,... | |
 | John Bonnycastle - 1835 - 308 páginas
...bring down the next three figures ; divide the number thus brought down by 300 times the square of the first figure of the root, and it will give the...the result from the dividend, and then bring down the next period, and so proceed till all the periods are brought down. For instance, in finding the... | |
 | John Bonnycastle - 1842 - 318 páginas
...300 times the square of the first figure of the root, and it will give the second figure ; add 800 times the square of the first figure, 30 times the...second figure together, for a divisor; then multiply thi* divisor by the second figure, and subtract the result from the dividend, and then bring down the... | |
 | John Bonnycastle - 1848 - 320 páginas
...bring down the next three figures ; divide the number thus brought down by 300 times the square of the first figure of the root, and it will give the...the result from the dividend, and then bring down the next period, and so proceed till all the periods are brought down. For instance, in finding the... | |
 | William Kent - 1907 - 1206 páginas
...after the first figure of the root as a trial second figure. Complete the divisor by adding to SCO times the square of the first figure, 30 times the product of the first by the second figure, and the square of the second figure. Multiply this divisor by the second figure;... | |
 | William Kent - 1902 - 1224 páginas
...after the first figure of the root as a trial second figuro . Complete the divisor by adding to 3GO times the square of the first figure, 30 times the product of the first by the second figure, and the square of the second figure. MulLipIv this divisor by the second figure;... | |
 | William Kent - 1910 - 1620 páginas
...quotient after the first figure of the root as a trial second figure. Complete the divisor by adding to 300 times the square of the first figure, 30 times the product of the first by the second figure, and the square of the second figure. Multiply this divisor by the second figure;... | |
 | Charles Haynes Hughes - 1917 - 774 páginas
...quotient after the first figure of the root as a trial second figure. Complete the divisor by adding to 300 times the square of the first figure, 30 times the product of the first by the second figure and the square of the second figure. Multiply this divisor by the second figure,... | |
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... number contained in the first period, and place the cube root of it in the quotient. Subtract its cube from the first period, and bring down the next three figures ; divide the number thus brought down by 300 times the square of the first figure of... 