Elements of Plane and Spherical Trigonometry with Logarithmic and Other Mathematical Tables and Examples of Their Use and Hints on the Art of Computation, Volumen2H. Holt, 1882 - 168 páginas |
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Página 25
... annual instalment of interest collected , the general result would be about the same as if it collected interest only once a year and in- vested it immediately . If r be the rate per cent per annum , the annual rate of increase Let us ...
... annual instalment of interest collected , the general result would be about the same as if it collected interest only once a year and in- vested it immediately . If r be the rate per cent per annum , the annual rate of increase Let us ...
Página 26
... annual interest was to be applied to the support of a student in Harvard College . What would be the income from the scholarship ? 3. If the sum of one cent had been put out at 3 per cent per annum at the Christian era , and accumulated ...
... annual interest was to be applied to the support of a student in Harvard College . What would be the income from the scholarship ? 3. If the sum of one cent had been put out at 3 per cent per annum at the Christian era , and accumulated ...
Página 28
... annual payments . Thus it is very common to pay a constant annual premium for a policy of life insurance . The value of such a series of payments at any epoch is found by reducing the value of each one to the epoch , allowing for ...
... annual payments . Thus it is very common to pay a constant annual premium for a policy of life insurance . The value of such a series of payments at any epoch is found by reducing the value of each one to the epoch , allowing for ...
Página 29
... annual payments of $ 85 each , of which the first is due in one year , the rate being 5 per cent ? We find by substitution Present value = 85 16 1.0515 . 1 1.051- 1.0515 85 1.0515-1 1.0515 .05 = 1700 ( 1.051 - 1 ) ( 1.05 ) 15 log 1.05 ...
... annual payments of $ 85 each , of which the first is due in one year , the rate being 5 per cent ? We find by substitution Present value = 85 16 1.0515 . 1 1.051- 1.0515 85 1.0515-1 1.0515 .05 = 1700 ( 1.051 - 1 ) ( 1.05 ) 15 log 1.05 ...
Página 30
... annual payments of $ 1000 Ans . $ 17,935 . each , the first due immediately , if the rate of interest is 3 per cent ? 4. A debtor owing $ 10,000 wishes to pay it in 10 equal annual instalments , the first being payable immediately . If ...
... annual payments of $ 1000 Ans . $ 17,935 . each , the first due immediately , if the rate of interest is 3 per cent ? 4. A debtor owing $ 10,000 wishes to pay it in 10 equal annual instalments , the first being payable immediately . If ...
Términos y frases comunes
9 Prop algebraic sign angles corresponding arithmetical complement binomial coefficient cent co-log column complementary angle computation corresponding number cosec cosine cotangent Cotg decimal point Diff Entering the table equation Example EXERCISES fifth find log find the logarithm find the number find the sine five places give log given logarithm given number half a unit increase interpolation last figure log a log log cot log sec log sin log sine loga logarithms of numbers mantissa minuend natural number negative number corresponding order of differences places of decimals present value quantities quotient rate of interest result rithms second differences sidereal SIMON NEWCOMB sine N sine or tangent sixth figure square Stirling's formula SUBTRACTION LOGARITHMS suppose table of logarithms Tang tenths of minutes trigonometric functions unity write wwww ww wwwww Δεν Δίν ΙΙ ΙΙΟ ΙΟ ΙΟΙ ΤΟ ន ន