 | Thomas Tate (mathematical master.) - 1848 - 284 páginas
...included angle. Since a parallelogram is double the area of the triangle cut off by a diagonal, it follows that, the area of a parallelogram is equal to the product of the two adjacent sides by the sine of the included angle. EXAMPLES. Ex. 1. The two sides of a triangle... | |
 | John Radford Young - 1855 - 218 páginas
...a parallelogram, and CE its altitude ; then, in the right-angled triangle AEC, we shall have _^* BO that the area of a parallelogram is equal to the product of any two adjacent sides multiplied by the sine of the angle between them. The trouble of finding the... | |
 | Henry Bartlett Maglathlin - 1869 - 332 páginas
...TRIANGLES AND QUADRILATERALS. 416i By Geometry, may be proved, in relation to areas, the following 1. The area of a PARALLELOGRAM is equal to the product of the base by the altitude. MENSURATION. This has been shown to be the case with a rectangle (Art. 210), and that... | |
 | Charles Davies - 1872 - 464 páginas
...denote the continued product of the number of linear units in each of the three lines. Thus, when we say that the area of a parallelogram is equal to the product of its base and altitude, we mean that the number of superficial units in the parallelogram is equal to... | |
 | Adrien Marie Legendre - 1874 - 500 páginas
...the continued product of the number of linear units in each of the three lines. Thus, -when we say that the area of a parallelogram is equal to the product of its base and altitude, we mean that the number of superficial units in the parallelogram is equal to... | |
 | Albert Newton Raub - 1877 - 348 páginas
...following are the rules for the measurements of triangles: It was proved in Denominate Numbers (Art. 107) that the area of a parallelogram is equal to the product of its base and altitude, and since a triangle is half a parallelogram, we derive the following RULE.... | |
 | William Guy Peck - 1877 - 430 páginas
...what is its altitude ? Ans. 16 ft. AREA OF A PARALLELOGRAM. 285. It is shown in Geometry (B. 4, P. 3), that the area of a parallelogram is equal to the product of its base and altitude; that is, Area of parallelogram = Base x Altitude. EXAM PLE S. 1. The base of... | |
 | Henry Bartlett Maglathlin - 1880 - 370 páginas
...QUADRILATERALS. 416. By Geometry may be proved, in relation to areas, the following PRINCIPLES. 1. The area of a PARALLELOGRAM is equal to the product of the base by the altitude. What is a Quadrilateral * A Parallelogram 1 A Rectangle 1 A Rhomboid 1 A Rhombus"... | |
 | George Anthony Hill - 1880 - 348 páginas
...two positions shown in the figure. Corollaries. — i. By combining this theorem with § 126, we see that the area of a parallelogram is equal to the product of its base by its altitude. 2. All parallelograms having equal bases and equal altitudes are equivalent.... | |
 | Henry Bartlett Maglathlin - 1882 - 398 páginas
...rhombus ABCD is equal to the rectangle EEC F of the same base and altitude (Art. 218). I—A f D HenC6> The area of a parallelogram is equal to the product of the base and altitude. 9. What is the area of a parallelogram whose base is 36 feet and altitude 15 feet ? 10.... | |
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Prove that the area of a parallelogram is equal to the product of the base, the diagonal, and the sine of the angle included by them. 
