Mathematics: Mechanic's bids and estimates. Mensuration for beginners. Easy lessons in geometrical drawing. Elementary algebra. A first course in geometry. .... I.. II.. III.. IV.. V.Seymour Eaton Doubleday & McClure Company, 1899 - 340 páginas |
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Página 45
... Square Root It is necessary here that the student should understand how to find the square root of large numbers . The square of a number is the product of the number by itself ; as , 25 is the square of 5 , 16 is the square of 4. The ...
... Square Root It is necessary here that the student should understand how to find the square root of large numbers . The square of a number is the product of the number by itself ; as , 25 is the square of 5 , 16 is the square of 4. The ...
Página 46
... square root . EXERCISES Find the square root in each instance : 1. 625 . 9. 21,025 . 17. 5625 . 24. 17,424 . 2. 3025 . 10. 77,284 . 18. 4096 . 25. 21,025 . 3. 5476 . 11. 196 . 19. 5184 . 26. 16,384 . 4. 9604 . 12. 225 . 20. 6561 . 27 ...
... square root . EXERCISES Find the square root in each instance : 1. 625 . 9. 21,025 . 17. 5625 . 24. 17,424 . 2. 3025 . 10. 77,284 . 18. 4096 . 25. 21,025 . 3. 5476 . 11. 196 . 19. 5184 . 26. 16,384 . 4. 9604 . 12. 225 . 20. 6561 . 27 ...
Página 47
... square root of 36 is 6 . Therefore , the area of the triangle as found by the rule is 6 sq . ft . But we already know ( see Lesson No. 5 ) that the area of a right - angled triangle is found by multiplying the base by the height and ...
... square root of 36 is 6 . Therefore , the area of the triangle as found by the rule is 6 sq . ft . But we already know ( see Lesson No. 5 ) that the area of a right - angled triangle is found by multiplying the base by the height and ...
Página 108
... square root of their product , and multiply the sum thus found by one - third the height . Lesson No. 22 1. Answer : 1240 in . multiplying by 144 ; by 11 . Reduce 2170 ft . to inches by then divide by ( 14 × 12 ) , and 2. Answer ...
... square root of their product , and multiply the sum thus found by one - third the height . Lesson No. 22 1. Answer : 1240 in . multiplying by 144 ; by 11 . Reduce 2170 ft . to inches by then divide by ( 14 × 12 ) , and 2. Answer ...
Página 109
... square mile , or a piece of land 80 ch . on each side . To find the distance from the center to B , square the two sides , add , and take one- half of the square root . There are 80 ch . in a mile . 802 + 802 = 12,800 . The square root ...
... square mile , or a piece of land 80 ch . on each side . To find the distance from the center to B , square the two sides , add , and take one- half of the square root . There are 80 ch . in a mile . 802 + 802 = 12,800 . The square root ...
Términos y frases comunes
9 ft ABCD acres adjacent angles algebra angle ABC angle ACB angle BAC angle EDF angle equal Answer axle base BC Bisect breadth bricks circle circumference Construction cube cubic foot cylinder describe arcs diagonal diagram diameter Divide draw equal in area equilateral triangle expression exterior angle fence figure Find the area Find the cost Find the number Find the value floor given line given straight line greater highest common factor hypotenuse inches isosceles triangle Join Lesson Let ABC lever measure multiply number of cubic number of square opposite angle parallel parallelogram perpendicular plane Proof Proposition 31 Prove pulley QUESTIONS AND EXERCISES radius rectangle rectangular right angles right-angled triangle rule of signs shown sides solid square root square yard surface THEOREM thick triangle ABC wall weight wide
Pasajes populares
Página 307 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Página 319 - Triangles upon the same base, and between the same parallels, are equal to one another.
Página 300 - Any two sides of a triangle are together greater than the third side.
Página 326 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 312 - If a straight line fall on two parallel straight lines, it makes the alternate angles equal to one another,and the exterior angle equal to the interior and opposite angle on the same side ; and also the two interior angles on the same side together equal to two right angles.
Página 332 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Página 283 - If two angles of a triangle be equal to one another, the sides also which subtend, or are opposite to, the equal angles, shall be equal to one another.
Página 314 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line.
Página 279 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Página 268 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.