Tables of Logarithms of Numbers and of Sines and Tangents for Every Ten Seconds of the Quadrant: With Other Useful TablesHarper & brothers, 1859 - 150 páginas |
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Página 32
... hypothenuse . Let the triangle CAB be right angled at A , then will R : CA :: tang . C : AB :: sec . C : CB . From the point C as a center , with a radius equal to the radius of the tables , B F E D A describe the arc DE , and from the ...
... hypothenuse . Let the triangle CAB be right angled at A , then will R : CA :: tang . C : AB :: sec . C : CB . From the point C as a center , with a radius equal to the radius of the tables , B F E D A describe the arc DE , and from the ...
Página 33
... hypothenuse and the angles ; 2. The hypothenuse and a leg ; 3. One leg and the angles ; or , 4. The two legs . All of these cases may be solved by the two preceding theo- rems . CASE I. ( 44. ) Given the hypothenuse and the angles , to ...
... hypothenuse and the angles ; 2. The hypothenuse and a leg ; 3. One leg and the angles ; or , 4. The two legs . All of these cases may be solved by the two preceding theo- rems . CASE I. ( 44. ) Given the hypothenuse and the angles , to ...
Página 34
... hypothenuse 275 2.439333 As the cosine of C 57 ° 23 ' 9.731602 To the base 148.23 2.170935 . Ex . 2. Given the hypothenuse 67.43 , and the angle at the perpendicular 38 ° 43 ′ , to find the base and perpendicular . Ans . The base is ...
... hypothenuse 275 2.439333 As the cosine of C 57 ° 23 ' 9.731602 To the base 148.23 2.170935 . Ex . 2. Given the hypothenuse 67.43 , and the angle at the perpendicular 38 ° 43 ′ , to find the base and perpendicular . Ans . The base is ...
Página 35
... hypothenuse 332.49 , and the perpendicu lar 98.399 , to find the angles and the base . Ans . The angles are 17 ° 12 ... hypothenuse . This case is solved by Theorem II . Radius : base :: tangent of the angle at the base : the perpen ...
... hypothenuse 332.49 , and the perpendicu lar 98.399 , to find the angles and the base . Ans . The angles are 17 ° 12 ... hypothenuse . This case is solved by Theorem II . Radius : base :: tangent of the angle at the base : the perpen ...
Página 36
... hypothenuse and angles . This example , it will be seen , falls under Case IV . 2. Given the hypothenuse 324 , and the angle at the base 48 ° 17 ' , to find the base and perpendicular . 3. Given the perpendicular 543 , and the angle at ...
... hypothenuse and angles . This example , it will be seen , falls under Case IV . 2. Given the hypothenuse 324 , and the angle at the base 48 ° 17 ' , to find the base and perpendicular . 3. Given the perpendicular 543 , and the angle at ...
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Términos y frases comunes
9 I I altitude angle of elevation arithm base chains circle Co-sine Co-tangent complement computed correction cosecant course and distance decimal diameter diff difference of latitude difference of longitude Dist divided equal equator fifth figure find the angles find the area find the Logarithm frustum given number given the angle height Hence horizontal plane hypothenuse inches latitude and departure length LO LO LO logarithmic sine measured meridian middle latitude miles minutes Multiply natural number nautical miles parallel parallel sailing perpendicular places plane sailing Prob Prop proportional quadrant radius Required the logarithmic right-angled spherical triangle right-angled triangle Sandy Hook secant ship sails side AC spherical triangle ABC SPHERICAL TRIGONOMETRY station subtract surface tabular number tang Tangent telescope theodolite Theorem vernier vertical Vulgar Fraction wyll yards zoids ΙΙ ΙΟ
Pasajes populares
Página 20 - The circumference of every circle is supposed to be divided into 360 equal parts, • called degrees, each degree into 60 minutes, and each minute into 60 seconds, etc.
Página 163 - In any spherical triangle, the sines of the sides are proportional to the sines of the opposite angles. In the case of right-angled spherical triangles, this proposition has already been demonstrated.
Página 69 - FIND the area of the sector having the same arc with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector.
Página 54 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Página 69 - TO THE NUMBER OF DEGREES IN THE ARC ; So IS THE AREA OF THE CIRCLE, TO THE AREA OF THE SECTOR.
Página 73 - To find the solidity of a pyramid. RULE. Multiply the area of the base by one third of the altitude.
Página vi - The characteristic of the logarithm of ANY NUMBER GREATER THAN UNITY, is one less than the number of integral figures in the given number.
Página 184 - If a heavy sphere, whose diameter is 4 inches, be let fall into a conical glass, full of water, whose diameter is 5, and altitude 6 inches ; it is required to determine how much water will run over ? AHS.