Tables of Logarithms of Numbers and of Sines and Tangents for Every Ten Seconds of the Quadrant: With Other Useful TablesHarper & brothers, 1859 - 150 páginas |
Dentro del libro
Resultados 1-5 de 35
Página 29
... method may be employed for several of the first degrees of the quadrant , if the proportional parts at the bottom of the page are not thought sufficiently precise . This correc- tion may , however , be obtained pretty nearly by ...
... method may be employed for several of the first degrees of the quadrant , if the proportional parts at the bottom of the page are not thought sufficiently precise . This correc- tion may , however , be obtained pretty nearly by ...
Página 30
... method will , of course , furnish cosines and cotan gents of arcs near 90 ° . ( 39. ) The secants and cosecants are omitted in this table , since they are easily derived from the cosines and sines . We R2 have found , Art . 28 , secant ...
... method will , of course , furnish cosines and cotan gents of arcs near 90 ° . ( 39. ) The secants and cosecants are omitted in this table , since they are easily derived from the cosines and sines . We R2 have found , Art . 28 , secant ...
Página 31
... method for the last two degrees of the quadrant when a tangent is given ; but near the limits of the quadrant it is better to employ the auxiliary table on page 114. The tabular number on page 114 is equal to log . sin . A - log . A ...
... method for the last two degrees of the quadrant when a tangent is given ; but near the limits of the quadrant it is better to employ the auxiliary table on page 114. The tabular number on page 114 is equal to log . sin . A - log . A ...
Página 34
... methods . He may then employ either method , as may appear to him most expeditious . CASE II . ( 45. ) Given the hypothenuse and one leg , to find the angles and the other leg . This case is solved by Theorem I. : Hypothenuse radius ...
... methods . He may then employ either method , as may appear to him most expeditious . CASE II . ( 45. ) Given the hypothenuse and one leg , to find the angles and the other leg . This case is solved by Theorem I. : Hypothenuse radius ...
Página 58
... method will give the sines correct to five decimal places , as far as two degrees . By the follow- ing method they may be obtained with greater accuracy for the entire quadrant . By Art . 75 , we have , by transposition , sin . ( a + b ) ...
... method will give the sines correct to five decimal places , as far as two degrees . By the follow- ing method they may be obtained with greater accuracy for the entire quadrant . By Art . 75 , we have , by transposition , sin . ( a + b ) ...
Otras ediciones - Ver todas
Términos y frases comunes
9 I I altitude angle of elevation arithm base chains circle Co-sine Co-tangent complement computed correction cosecant course and distance decimal diameter diff difference of latitude difference of longitude Dist divided equal equator fifth figure find the angles find the area find the Logarithm frustum given number given the angle height Hence horizontal plane hypothenuse inches latitude and departure length LO LO LO logarithmic sine measured meridian middle latitude miles minutes Multiply natural number nautical miles parallel parallel sailing perpendicular places plane sailing Prob Prop proportional quadrant radius Required the logarithmic right-angled spherical triangle right-angled triangle Sandy Hook secant ship sails side AC spherical triangle ABC SPHERICAL TRIGONOMETRY station subtract surface tabular number tang Tangent telescope theodolite Theorem vernier vertical Vulgar Fraction wyll yards zoids ΙΙ ΙΟ
Pasajes populares
Página 20 - The circumference of every circle is supposed to be divided into 360 equal parts, • called degrees, each degree into 60 minutes, and each minute into 60 seconds, etc.
Página 163 - In any spherical triangle, the sines of the sides are proportional to the sines of the opposite angles. In the case of right-angled spherical triangles, this proposition has already been demonstrated.
Página 69 - FIND the area of the sector having the same arc with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector.
Página 54 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Página 69 - TO THE NUMBER OF DEGREES IN THE ARC ; So IS THE AREA OF THE CIRCLE, TO THE AREA OF THE SECTOR.
Página 73 - To find the solidity of a pyramid. RULE. Multiply the area of the base by one third of the altitude.
Página vi - The characteristic of the logarithm of ANY NUMBER GREATER THAN UNITY, is one less than the number of integral figures in the given number.
Página 184 - If a heavy sphere, whose diameter is 4 inches, be let fall into a conical glass, full of water, whose diameter is 5, and altitude 6 inches ; it is required to determine how much water will run over ? AHS.