A Textbook on Plumbing, Heating, and Ventilation, Volumen51897 |
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Página 9
... quotient . The product of all the uncanceled numbers in the dividend equals 2 × 1 × 4 × 1 = 8 ; the product of all the uncanceled numbers in the divisor equals 1 x 1 x 1x1 = 1 . Hence , Or , 2 6 2 X 1 X 4 X 1 1 x 1 x 1 x 1 - 4 1 72 × 48 ...
... quotient . The product of all the uncanceled numbers in the dividend equals 2 × 1 × 4 × 1 = 8 ; the product of all the uncanceled numbers in the divisor equals 1 x 1 x 1x1 = 1 . Hence , Or , 2 6 2 X 1 X 4 X 1 1 x 1 x 1 x 1 - 4 1 72 × 48 ...
Página 25
... quotient of .5 , the decimal point being placed before the one figure of the quotient , or .5 , since only one cipher was annexed to the numerator . Ans . 77 8 ) 7.000 5 32 ) 5.00000 ( .15625 Ans . .875 Ans . 32 Since .65 = 65 100 ' 65 ...
... quotient of .5 , the decimal point being placed before the one figure of the quotient , or .5 , since only one cipher was annexed to the numerator . Ans . 77 8 ) 7.000 5 32 ) 5.00000 ( .15625 Ans . .875 Ans . 32 Since .65 = 65 100 ' 65 ...
Página 26
... Ans . 25 +39 64 There are three deci- mal places in the quotient , since three ciphers were annexed to the dividend . 930 64 314 256 588 576 120 64 560 512 480 448 320 320 ( d ) 40.6 + 7.1 40.67.1 × ( 3.029 26 ARITHMETIC .
... Ans . 25 +39 64 There are three deci- mal places in the quotient , since three ciphers were annexed to the dividend . 930 64 314 256 588 576 120 64 560 512 480 448 320 320 ( d ) 40.6 + 7.1 40.67.1 × ( 3.029 26 ARITHMETIC .
Página 27
... quotient . 2037 6230 6111 119 ( 59 ) 175 200 = of a foot . 8 .875 = 875 1,000 = 1 foot 12 inches . 3 7 78 7 12 of 1 foot = 8 1 21 22 || 2 = 10 10/1 inches . Ans . ( 60 ) 12 inches = 1 foot . 3 of an inch = 16 3 ÷ 12 = 16 3 1 1 X = of a ...
... quotient . 2037 6230 6111 119 ( 59 ) 175 200 = of a foot . 8 .875 = 875 1,000 = 1 foot 12 inches . 3 7 78 7 12 of 1 foot = 8 1 21 22 || 2 = 10 10/1 inches . Ans . ( 60 ) 12 inches = 1 foot . 3 of an inch = 16 3 ÷ 12 = 16 3 1 1 X = of a ...
Página 37
... quotient . ( c ) .375 × 5 .125 .375 = -- = ? 375 75 = - We shall solve this problem by first reducing the decimals to their equiva- lent common fractions . - 15 3 3 1 3 Х - 1,000 200 40 8 the numerator of the fraction . = or the value ...
... quotient . ( c ) .375 × 5 .125 .375 = -- = ? 375 75 = - We shall solve this problem by first reducing the decimals to their equiva- lent common fractions . - 15 3 3 1 3 Х - 1,000 200 40 8 the numerator of the fraction . = or the value ...
Términos y frases comunes
00 gauge amperes angles annex Applying rule B. T. U. per hour base Base percentage boiler candle power Cast Iron ciphers circle circular mils circumference column combustion consequently considered any longer contained copper cubic feet cubic foot decimal places diameter difference distance divided dividend equals erased entirely figure flame floor flow flue flush following the title formula frustum gallons heating surface Hence hundredths improper fraction joint length lowest denomination metal minuend minute mixed number multiplicand multiplier nearly obtained percentage pounds pressure quotient radiator reduce remaining reserve root seams shown in Fig solder square feet square foot square inches steam STRENGTHS OF MATERIALS strokes subtract Table tank temperature ten-thousands thousandths trap trial divisor triangle tube valve velocity volts volume water hammer weight whole numbers wiped wire write yards zinc
Pasajes populares
Página 16 - Operations with Fractions A) To change a mixed number to an improper fraction, simply multiply the whole number by the denominator of the fraction and add the numerator.
Página 67 - Divide the difference in temperature, between that at which the room is to be kept and the coldest outside atmosphere, by the difference between the temperature of the steam pipes and that at which you wish to keep the room, and the product will be the square feet, or fraction thereof of plate or pipe surface to each square foot of glass (or its equivalent in wall surface).
Página 4 - In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces it.
Página 51 - The pressure exerted by a fluid in any direction upon any plane surface is equal to the weight of a prism of the fluid whose base is the projection of the surface at right angles to the...
Página 108 - In any proportion, the product of the means equals the product of the extremes.
Página 18 - If necessary, reduce the fractions to a common denominator, add the numerators, and write the sum over the common denominator.
Página 66 - Ascertain the weight of moisture in the air before it is heated, and compute the weight of moisture required to produce the desired degree of humidity in the same weight of air at the temperature at which it is to be used; the difference between the quantities of moisture thus found will be the amount of moisture to be supplied. EXAMPLE. — A certain room is supplied with air having a temperature at the registers of 120°, at the rate of 300 cubic feet per minute.
Página 120 - An angle inscribed in a circle is measured by one-half the intercepted arc. In this case, the angle intercepts one-fourth the circumference, and is measured by one-eighth the circumference, or by 360° X 5- = 45°.