EXAMPLE. Ch. L. There is a ditch 14. 25 long, by the side of which it is required lo lay out an oblong piece of ground, which shall contain 3A. OR. 27P: what breadth must be laid off at each end of the ditch to enclose the 3A. OR. 37P? To find the content of a piece of ground, in form of an oblique angular parallelogram; or of a rhombus, or rhombodies. Multiply the base into the perpendicular height. The reason is plain from theo. 13. sect. 1. Plate VII. fig. 2. EXAMPLE. Let ABCD be a piece of ground in form of a rhombus, whose base AB is 22 chains, and perpendicular DE, or FC, 20 chains. Required the The converse of this is done by prob. 4. and the map is drawn, by laying off the perpendicular on that part of the base from whence it was taken : joining the extremity thereof to that of the base, by a right line, and thence complete the parallelogram. PROBLEM VI. To find the content of a triangular piece of ground. Multiply the base by half the perpendicular, or the perpendicular by half the base; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor. 2. theo. 12. Let ABC be a triangular piece of ground, whose longest side or base BC, is 24C. 38L. and perpendicular AD, let fall from the opposite angle, is 13 C. 28L. Required the content. Ch. L. Ch. L. Perp. 13. 28 6. 78) four-pole chains, by prob. perp. 6. 39-3.39) 1. sect. 3. Or 2dly. Perp. 6.78 of four-pole chains. base 6.19 6102 678 4068 A. R. P. 4119682 4.0. 31. Or 3dly. Base 12.38 four-pole chains. Or the base and perpendicular may be reduced to perches; and the content may be thence obtained, thus: |