The Elements of Euclid |
Dentro del libro
Resultados 1-3 de 82
Página 407
And if a triangle ABC has a given angle ABC , the rec- 66 . tangle AB , BC contained by the fides about that angle , fhall have a given ratio to the triangle ABC . Complete the parallelogram ABCD ; therefore , by this Propofi- tion ...
And if a triangle ABC has a given angle ABC , the rec- 66 . tangle AB , BC contained by the fides about that angle , fhall have a given ratio to the triangle ABC . Complete the parallelogram ABCD ; therefore , by this Propofi- tion ...
Página 418
LXXIV . a triangle has a given obtufe angle ; the excefs of the fquare of the fide which fubtends the obtuse an- gle above the fquares of the fides which contain it , fhall have a given ratio to the triangle . Let the triangle ABC have ...
LXXIV . a triangle has a given obtufe angle ; the excefs of the fquare of the fide which fubtends the obtuse an- gle above the fquares of the fides which contain it , fhall have a given ratio to the triangle . Let the triangle ABC have ...
Página 425
OPQ . because , as has been fhewn , the ratio of AD to BC is the fame with the ratio of ( HF to FL , that is , by the construction , with the ratio of ) OR to PQ ; and the angle BAC is equal to the angle POQ , therefore the triangle ABC ...
OPQ . because , as has been fhewn , the ratio of AD to BC is the fame with the ratio of ( HF to FL , that is , by the construction , with the ratio of ) OR to PQ ; and the angle BAC is equal to the angle POQ , therefore the triangle ABC ...
Comentarios de la gente - Escribir un comentario
No encontramos ningún comentario en los lugares habituales.
Otras ediciones - Ver todas
Términos y frases comunes
added alfo alſo altitude angle ABC angle BAC bafe baſe becauſe bifected Book Book XI circle circle ABCD circumference common cone cylinder defcribed Definition demonftrated diameter divided double draw drawn equal equal angles equiangular equimultiples excefs fame fame multiple fecond fegment fhall fhewn fides fimilar firft firſt folid folid angle fore four fourth fquare fquare of BC ftraight line given angle given ftraight line given in fpecies given in pofition given magnitude given ratio greater Greek half join lefs magnitude manner meet oppofite parallel parallelogram perpendicular plane produced PROP Propofition proportionals pyramid reafon rectangle remaining right angles ſphere taken THEOR theſe third thro triangle ABC wherefore whole