Imágenes de páginas
PDF
EPUB

The next less logarithm in the table is .3674, and the three corresponding figures of the natural number are 233. Their logarithm is less than the one proposed by 11, and the tabular difference is 18. By referring to the margin of page 291, we find that, with a difference of 18, the figure corresponding to the proportional part 11 is 6. Hence, since the characteristic of the proposed logarithm is 3, the required natural number is 2336.

EXAMPLES.

1. Find the number corresponding to the logarithm 2.5386. Ans. 345.6.

2. Find the number corresponding to the logarithm 0.2345. Ans. 1.716.

3. Find the number corresponding to the logarithm 1.9946. Ans. 98.76.

4. Find the number corresponding to the logarithm 1.6478. Ans. 0.4444.

[ocr errors]

411. Multiplication by Logarithms.—According to Art. 396, to find the product of two numbers we have the following

RULE.

Add the logarithms of the factors; the sum will be the logarithm of the product.

The word sum is here to be understood in its algebraic sense. The decimal part of a logarithm is invariably positive; but the characteristic may be either positive or negative.

Ex. 1. Find the product of 57.98 by 3.12.

[merged small][ocr errors][merged small][merged small]

The log. of the product 180.9 is 2.2575.
Ex. 2. Find the product of 0.00563 by 172.5.

The logarithm of 0.00563 is 3.7505.
172.5 is 2.2368.

[ocr errors]

The log. of the product 0.971 is 1.9873.
Ex. 3. Find the product of 54.32 by 6.543.
Ex. 4. Find the product of 3.854 by 0.5761.

412. Division by Logarithms.—According to Art. 397, to find the quotient of two numbers we have the following

RULE.

From the logarithm of the dividend subtract the logarithm of the divisor; the difference will be the logarithm of the quotient.

The word difference is here to be understood in its algebraic sense; the decimal part of the logarithm being invariably positive, while the characteristic may be either positive or negative.

Ex. 1. Find the quotient of 888.7 divided by 42.24.
The logarithm of 888.7 is

42.24 is

2.9488.

1.6257.

The quotient is 21.04, whose log. is 1.3231.

Ex. 2. Find the quotient of 0.8692 divided by 42.32.
The logarithm of 0.8692 is

[ocr errors][merged small]

1.9391.

1.6265.

The quotient is 0.002054, whose log. is 2.3126.

Ex. 3. Find the quotient of 380.7 divided by 13.75.
Ex. 4. Find the quotient of 24.93 divided by .0785.

413. Involution by Logarithms.-According to Art. 398, to involve a number to any power we have the following

RULE.

Multiply the logarithm of the number by the exponent of the power required.

It should be remembered that what is carried from the decimal part of the logarithm is positive, whether the characteristic be positive or negative.

Ex. 1. Find the fifth power of 2.846.

The logarithm of 2.846 is

0.4542.

5

The fifth power is 186.65, whose log. is 2.2710.
Ex. 2. Find the cube of .07654.

The logarithm of .07654 is

2.8839.
3

The cube is 0.0004484, whose log. is 4.6517.

Ex. 3. Find the 20th power of 1.06.

Ex. 4. Find the 'seventh power of 0.8952.

414. Evolution by Logarithms.—According to Art. 399, to extract any root of a number we have the following

RULE.

Divide the logarithm of the number by the index of the root required.

Ex. 1. Find the cube root of 482.4.

The logarithm of 482.4 is 2.6834.

Dividing by 3, we have 0.8945, which corresponds to 7.843, which is therefore the root required.

Ex. 2. Find the 100th root of 365.

Ans. 1.061.

When the characteristic of the logarithm is negative, and is not divisible by the given divisor, we may increase the characteristic by any number which will make it exactly divisible, provided we prefix an equal positive number to the decimal part of the logarithm.

Ex. 3. Find the seventh root of 0.005846.

The logarithm of 0.005846 is 3.7669, which may be written 7+4.7669.

Dividing by 7, we have 1.6810, which is the logarithm of .4797, which is therefore the root required.

Ex. 4. Find the 10th root of 0.007815.

415. Proportion by Logarithms.-The fourth term of a proportion is found by multiplying together the second and third terms and dividing by the first. Hence, to find the fourth term of a proportion by logarithms, we have the following

RULE.

Add the logarithms of the second and third terms, and from their sum subtract the logarithm of the first term.

Ex. 1. Find a fourth proportional to 72.34, 2.519, and 357.5. Ans. 12.45.

Ex. 2. Find a fourth proportional to 43.17, 275, and 5.762. Ex. 3. Find a fourth proportional to 5.745, 781.2, and 54.27.

Exponential Equations.

416. An exponential equation is one in which the unknown quantity occurs as an exponent. Thus,

ax-b

is an exponential equation, from which, when a and b are known, the value of x may be found. If a=2 and b=8, the equation becomes 2x=8,

in which the value of x is evidently 3, since 23-8. If a 16 and b=2, the equation becomes

162-2,

in which the value of x is evidently, since 16*=2.

417. Solution by Logarithms.—When b is not an exact power or root of a, the equation is most readily solved by means of logarithms. Taking the logarithm of each member of the equation ab, we have

[merged small][merged small][merged small][ocr errors][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][ocr errors]

Compound Interest.

418. Interest is money paid for the use of money. When the interest, as soon as it becomes due, is added to the principal, and interest is charged upon the whole, it is called compound interest.

419. To find the amount of a given sum in any time at compound interest. It is evident that $1.00 at 5 per cent. interest becomes at the end of the year a principal of $1.05; · and, since the amount at the end of each year must be proportioned to the principal at the beginning of the year, the amount at the end of two years will be given by the proportion

1.00: 1.05 1.05: (1.05)2.

The sum (1.052) must now be considered as the principal, and the amount at the end of three years will be given by the proportion

1.00: 1.05: (1.05): (1.05)3.

In the same manner, we find that the amount of $1.00 for n years at 5 per cent. compound interest is (1.05)".

For the same reason, the amount for n years at 6 per cent. is (1.06)". It is also evident that the amount of P dollars for a given time must be P times the amount of one dollar.

Hence, if we put

P to represent the principal,

r the interest of one dollar for one year,

n the number of years for which interest is taken,
A the amount of the given principal for n years,

we shall have

A=P(1+r)".

This equation contains four quantities, A, P, n, r, any three of which being given, the fourth may be found. The computation is most readily performed by means of logarithms. Taking the logarithms of both members of the preceding equation and reducing, we find

log. A=log. P+nxlog.(1+r),
log. P=log. A−n × log. (1+r),

[merged small][merged small][merged small][ocr errors][merged small][merged small]
« AnteriorContinuar »