A Treatise on AlgebraHarper & Brothers, 1868 - 384 páginas |
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Página iii
... become necessary to cast them , aside , I decided to improve the opportunity to make a thorough revision of the work . I therefore solicited criticisms from several college pro- fessors who had had much experience in the use of this ...
... become necessary to cast them , aside , I decided to improve the opportunity to make a thorough revision of the work . I therefore solicited criticisms from several college pro- fessors who had had much experience in the use of this ...
Página 55
... become necessary . It may happen that the first term of the arranged dividend is not divisible by the first term of the divisor . This may arise from the presence of a factor in the divisor which is not found in the dividend , and may ...
... become necessary . It may happen that the first term of the arranged dividend is not divisible by the first term of the divisor . This may arise from the presence of a factor in the divisor which is not found in the dividend , and may ...
Página 69
... common denominator , the fractions become 2 Зох 2x and 6 6 ' Бас Adding the numerators , we obtain 6 ° It is plain that three sixths of x and two sixths of x make five sixths of x . α C 2. What is the sum of and m FRACTIONS . 69.
... common denominator , the fractions become 2 Зох 2x and 6 6 ' Бас Adding the numerators , we obtain 6 ° It is plain that three sixths of x and two sixths of x make five sixths of x . α C 2. What is the sum of and m FRACTIONS . 69.
Página 71
... become 10x 9x and 15 15 ° 10x 9x X Hence we have 15 15—15 ; and it is plain that ten fifteenths of x , diminished by nine fif teenths of x , equals one fifteenth of x . 2. From 12x 7 3x subtract 5 9a - 4x Ба - 3x 3. From subtract 7 3 It ...
... become 10x 9x and 15 15 ° 10x 9x X Hence we have 15 15—15 ; and it is plain that ten fifteenths of x , diminished by nine fif teenths of x , equals one fifteenth of x . 2. From 12x 7 3x subtract 5 9a - 4x Ба - 3x 3. From subtract 7 3 It ...
Página 79
... x , the first member becomes 3x7-4 ; that is , 21-4 , or 17 ; and the second member be- } comes 24-7 ; that is , 17. Hence 7 is EQUATIONS OF THE FIRST DEGREE . 79 EQUATIONS OF THE FIRST DEGREE Definitions-Axioms employed PAGE.
... x , the first member becomes 3x7-4 ; that is , 21-4 , or 17 ; and the second member be- } comes 24-7 ; that is , 17. Hence 7 is EQUATIONS OF THE FIRST DEGREE . 79 EQUATIONS OF THE FIRST DEGREE Definitions-Axioms employed PAGE.
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Términos y frases comunes
algebraic arithmetical progression binomial binomial theorem cent coefficient common denominator common difference compound interest continued fraction cube root decimal denote digits Divide the number dividend divisible dollars equa equal equation whose roots EXAMPLES exponent expression Extract the square factors figure Find the cube Find the fifth Find the fourth Find the number Find the square Find the sum find the values following RULE fourth power geometrical progression Given greatest common divisor Hence indicates infinite series last term least common multiple less logarithm miles monomial Multiply negative nth root number of terms obtain polynomial positive preceding Prob problem quotient radical sign ratio real roots Reduce remainder represent Resolve result second degree second term Solve the equation square root Sturm's Theorem subtract suppose surd third tion unity unknown quantity whence whole number zero
Pasajes populares
Página 72 - Now .} of f- is a compound fraction, whose value is found by multiplying the numerators together for a new numerator, and the denominators for a new denominator.
Página 141 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Página 39 - ... the square of the second. In the second case, (ab)2 = a?-2ab + bi. (2) That is, the square of the difference of two numbers is equal to the square of the first, minus twice the product of the first by the second, plus the square of the second.
Página 54 - Divide the less number by the remainder, the last divisor by the last remainder, and so on, till nothing remains. The last divisor will be the greatest common divisor sought.
Página 46 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Página 181 - A vintner draws a certain quantity of wine out of a full vessel that holds 256 gallons ; and then filling the vessel with water, draws off the same quantity of liquor as before, and so on for four draughts, when there were only 81 gallons of pure wine left. How much wine did he draw each time ? 50.
Página 227 - In arithmetical progression there are five parts to be considered, viz : the first term, the last term, the number of terms, the common difference, and the sum of all the terms.
Página 204 - ... the product of the two, plus the square of the second. In the third case, we have (a + b) (a — 6) = a2 — b2. (3) That is, the product of the sum and difference of two quantities is equal to the difference of their squares.
Página 220 - In a series of equal ratios, any antecedent is to its consequent, as the sum of all the antecedents is to the sum of all the consequents. Let a: 6 = c: d = e :/. Then, by Art.
Página 202 - A , where m=c 9. Find two numbers such that their sum, their product, and the difference of their squares may be all equal to one another.