Primer of geometry |
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Página 6
... fall along DF , because the angle BAC is equal to the angle EDF ; also B would fall on E , because AB is equal to DE ; and C on F , because AC is equal to DF . Therefore the straight line BC would coincide with EF ; for if it fell ...
... fall along DF , because the angle BAC is equal to the angle EDF ; also B would fall on E , because AB is equal to DE ; and C on F , because AC is equal to DF . Therefore the straight line BC would coincide with EF ; for if it fell ...
Página 7
... fall along that of AB ; also B would fall on that of C , because AB is equal to AC , and C on that of B for the same reason . Therefore BC would fall on its former position . Thus AB , BC would fall on the former positions of AC , CB ...
... fall along that of AB ; also B would fall on that of C , because AB is equal to AC , and C on that of B for the same reason . Therefore BC would fall on its former position . Thus AB , BC would fall on the former positions of AC , CB ...
Página 8
... fall along ED , since the angle ABC is equal to the angle DEF ; and CA would fall along FD , since the angle ACB is equal to the angle DFE . Therefore the point A would fall on the point D , and the triangle ABC would coincide with the ...
... fall along ED , since the angle ABC is equal to the angle DEF ; and CA would fall along FD , since the angle ACB is equal to the angle DFE . Therefore the point A would fall on the point D , and the triangle ABC would coincide with the ...
Página 13
... fall along the former position of the other arm ; that is , so that ED might fall along the former position of EK , and EK along that of ED ; then would EK produced , or EF , fall along that of ED produced , or EL . Thus EF and ED would ...
... fall along the former position of the other arm ; that is , so that ED might fall along the former position of EK , and EK along that of ED ; then would EK produced , or EF , fall along that of ED produced , or EL . Thus EF and ED would ...
Página 18
... fall along GP , because HGP is equal to GHS ; and GX would fall along HR , because GHR is equal to HGQ . Therefore GP , HR would meet if produced towards P and R , and thus two straight lines would enclose a space , which is impossible ...
... fall along GP , because HGP is equal to GHS ; and GX would fall along HR , because GHR is equal to HGQ . Therefore GP , HR would meet if produced towards P and R , and thus two straight lines would enclose a space , which is impossible ...
Términos y frases comunes
ABC is equal adjacent sides ADVANCED TEXT-BOOK ANCIENT CLASSICS ATLAS Atlases Author BOTANY Cargilfield Preparatory School centre circumference CLASSICS FOR ENGLISH Crown 8vo DAVID PAGE describe a circle describe a triangle draw Durham University ENGLISH LANGUAGE ENGLISH PROSE ENGLISH READERS equilateral fall Fcap Fettes College former position GEOLOGY given angle given circle given point given straight line given triangle Half-bound HANDY HENRY ALLEYNE NICHOLSON included angle INTRODUCTORY TEXT-BOOK JAMES STORMONTH Join KEITH JOHNSTON LAPB Let the straight LL.D MANUAL OF ZOOLOGY MODERN GEOGRAPHY NATURAL HISTORY parallelogram PHYSICAL GEOGRAPHY PRQS Q.E.D. PROPOSITION radius rectilineal figure required to describe respectively equal revised and enlarged right angles Second Edition sides &c sides equal square on PQ straight line &c Students TEXT-BOOK OF PHYSICAL TEXT-BOOK OF ZOOLOGY touches the circle triangle ABC twice the rectangle WILLIAM BLACKWOOD ZOOLOGY
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