The Western Calculator, Or, A New and Compendious System of Practical Arithmetic: Containing the Elementary Principles and Rules of Calculation in Whole, Mixed, and Decimal Numbers ...Johnston & Stockton, 1839 - 203 páginas |
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Página 38
... gain ? Ans . prime cost 219 dolls . 371⁄2 cts . sold for 276 dolls . 75 cts . gain 57 dolls . 37 cts . 11. If 27 cwt . of sugar cost 471. 12s . 101d . what cost 1 cwt . ? Ans . 11. 15s . 3 d . 12. Suppose a man has an estate of 9708 ...
... gain ? Ans . prime cost 219 dolls . 371⁄2 cts . sold for 276 dolls . 75 cts . gain 57 dolls . 37 cts . 11. If 27 cwt . of sugar cost 471. 12s . 101d . what cost 1 cwt . ? Ans . 11. 15s . 3 d . 12. Suppose a man has an estate of 9708 ...
Página 60
... gain 50 dollars , when 80 dollars would gain it in 15 years ? Ans . 2 years . 12. If a traveller can perform a journey in 4 days , when the days are 12 hours long , what time will he the days are 16 hours long ? require when Ans . 3 ...
... gain 50 dollars , when 80 dollars would gain it in 15 years ? Ans . 2 years . 12. If a traveller can perform a journey in 4 days , when the days are 12 hours long , what time will he the days are 16 hours long ? require when Ans . 3 ...
Página 62
... gain 12 dollars on the whole ? ̧ · Ans . 2 dolls . 42+ cts . 5. If 225 pounds be carried 512 miles for 20 dollars , how many pounds may be carried 64 miles for the same money ? Ans . 1800lb . 6. If 87 dolls . 50 cents be assessed on ...
... gain 12 dollars on the whole ? ̧ · Ans . 2 dolls . 42+ cts . 5. If 225 pounds be carried 512 miles for 20 dollars , how many pounds may be carried 64 miles for the same money ? Ans . 1800lb . 6. If 87 dolls . 50 cents be assessed on ...
Página 63
... gain 143 dolls . Ans . 3 dolls . 674 cts . 7. If half a ton of hay was equally divided among 80 horses , how much must be given to 7 ? Ans . 3qr . 14lb . 8. Suppose the circumference of one of the larger wheels of a wagon to be 12 feet ...
... gain 143 dolls . Ans . 3 dolls . 674 cts . 7. If half a ton of hay was equally divided among 80 horses , how much must be given to 7 ? Ans . 3qr . 14lb . 8. Suppose the circumference of one of the larger wheels of a wagon to be 12 feet ...
Página 64
... gain as much in 1 month , as 127 dollars would gain in 12 months ? Ans . 1524 dolls . 17. If a pair of steelyards be 36 inches in length to the centre of motion , the pea 5 lb. and the draught end inch in length , what weight will they ...
... gain as much in 1 month , as 127 dollars would gain in 12 months ? Ans . 1524 dolls . 17. If a pair of steelyards be 36 inches in length to the centre of motion , the pea 5 lb. and the draught end inch in length , what weight will they ...
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Términos y frases comunes
100 dollars 16 feet 25 cents 9 inches acres amount annum arithmetical arithmetical progression barrels breadth bricks bushels cask cents per pound cents per yard ciphers common denominator compound compound interest cost cube root cubic currency decimal diameter divide the product dividend divisor dollars 50 cents dolls duodecimals equal EXAMPLES Federal money feet 6 inches feet 9 feet long figures foot gain gallons geometrical progression given number given sum half hogshead hundred improper fraction inches broad inches long interest length lowest terms measure miles mills mixed number months Note number of terms operation ounces paid payment pence perches piece of ground principal proportion quantity quotient Reduce remainder rods rule of three SECTION shillings side sold solid content square root subtract superficial tare thickness timber vulgar fraction wall weight whole numbers
Pasajes populares
Página 29 - LIQUID MEASURE 4 gills (gi.) = 1 pint (pt.) 2 pints = 1 quart (qt...
Página 59 - A and B depart from the same, place and travel the same road ; but A goes 5 days before B, at the rate of 15 miles a day . B follows at the rate of 20 miles a . day } what distance must he travel to overtake A ? Ans. 300 miles RULE OF THREE INVERSE.
Página 54 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Página 115 - RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator, then reduce the new fraction to its lowest term by Case I.
Página 154 - If the vessel be double-decked, take the length thereof from the fore part of the main stem, to the after part of the stern post, above the upper deck ; the breadth thereof at the broadest part above the main wales, half of which breadth shall be accounted the depth of such vessel, and then deduct from the...
Página 112 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Página 111 - A proper fraction is when the numerator is less than the den'omiuator ; as i, f , ££, &c.
Página 135 - To extract the Square Root of a Vulgar Fraction. RULE, Reduce the fraction to its lowest terms, then extract the square root of the numerator for a new numerator, and the square root of the denominator for a new denominator.
Página 121 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Página 65 - If a footman travel 130 miles in 3 days, when the days are 12 hours long ; in how many days, of 10 hours each, may he travel 360 miles ? Ans. 9|f days. 5. If 120 bushels of corn can serve 14 horses 56 days, how many days will 94 bushels serve 6 horses?