| Peter Nicholson - 1831 - 326 páginas
...of the same value ; but it is usual to arrange them according to the order of the alphabet. CASE II. When the multiplicand is a compound quantity and the multiplier a simple quantity. RULE. Multiply every term of the multiplicand by the multiplier, to each product prefix its proper... | |
| John Radford Young - 1832 - 760 páginas
[ Lo sentimos, el contenido de esta página está restringido. ] | |
| John Radford Young - 1839 - 332 páginas
...usual custom, is expected to arrange them according to their order in the alphabet. CASE П. (20.) When the multiplicand is a compound quantity, and the multiplier a simple quantity. Find the product of the multiplier and each term of the multiplicand separately, beginning at the left... | |
| Andrew Bell (writer on mathematics.) - 1839 - 500 páginas
...by — ANSWERS. 1. . . 60 аV/ 4. . . 2... — 18a4AeV 5... 3... — 28жАсУ*2 6--- — CASE IV. When the multiplicand is a compound quantity, and the multiplier a simple quantity. (67.) 1 Find the product of the multiplier, and each term of the multiplicand separately by the preceding... | |
| John Radford Young - 1851 - 266 páginas
...х 6. (11) — 2 (12) 5aô2an/2x— 2ox<xíж2^2 x— 3(о— 2o— 5a)xyz — o6. 26. CASE II — When the multiplicand is a compound quantity and the multiplier a simple quantity: — RULE. — Multiply each term of the compound factor by the simple factor, beginning at the left... | |
| William Somerville Orr - 1854 - 534 páginas
...— 13аахУх14а*л3у2 ух— 4a x— »>"-ху-|аУх— 36Vx— 10. 12. 8. iaxV CASE II. — When, the multiplicand is a compound quantity, and the multiplier a simple quantity. RULE. — Multiply each simple term in the multiplicand by the multiplier, beginning always at the... | |
| Barnard Smith - 1857 - 740 páginas
...xo' =a° *, £ -m+e a~mx aj = a ', /r~mv nn — n—m+n Ex. XI. A. Examples in multiplication, where the multiplicand is a compound quantity, and the multiplier a simple quantity, worked out. Ex.1. 3aoi-2ay + is Ex.2. 6V -2^ + #-4. 4a Ex.3. —ox + by—Scs? Ex.4 #'— d Ex.5. 2a"... | |
| James Cahill (of Dublin.) - 1875 - 230 páginas
...a2Xa2=a5; for a2Xa2=aXaXaXaXa=a6. Similarly 4a262 X5a264=20a566 ; and x™ Xz" =xm+n 35. CASE П — When the multiplicand is a compound quantity, and the multiplier a simple one. Rule — Multiply each term of the multiplicand by the multiplier as in Case I, beginning at the... | |
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